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ycow [4]
2 years ago
5

Under normal conditions, 1.5 feet of snow will melt into 2 inches of water. During a winter season high in the mountains, 49 fee

t of snow fell. How many inches of water will there be when the snow melts?
Mathematics
2 answers:
iren [92.7K]2 years ago
4 0

Answer:

Step-by-step explanation:

65.333332

Bogdan [553]2 years ago
4 0

Answer: 69.2 inches

Step-by-step explanation: This is a ration problem.  First, convert all feet into inches and then set up the problem.  17 inches is to 2 inches as 588 inches is to x

17/2  = 558/x

If we divide 588 by 17 that will give us 34.6, the factor we need to multiply 2 by to get inches., which is 69.2.  

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Ainat [17]
6z to the 4th power - 2z to the 3rd power
5 0
3 years ago
1) A medium cookies and creme milkshake at The
Leya [2.2K]

Answer:

You will pay $4.31

Step-by-step explanation:

I know this because a fourth of $5.75 is 1.4375 so you would  round it to $1.44 and then $5.75 - $1.44 is $4.31.

So you will pay $4.31 for one milkshake.

5 0
3 years ago
The center will buy bulk bags of wildflower seed to divide into small packets and
just olya [345]
I need point thx you
5 0
3 years ago
A fenced in rectangular region with the dimensions 4 yards by 8 yards is suddenly expanded by the same distance in each dimensio
Korolek [52]

Answer:

The distance added to each dimension is 2 yards.

Step-by-step explanation:

The initial dimensions of the rectangular fence is 8 yards by 4 yards.

The initial area of the rectangular fence = area of a rectangle

area of a rectangle = length x width

So that,

The initial area of the fence = 8 x 4

                                              = 32

The initial area of the fence is 32 square yards.

But, with the new dimensions, area = 60 square yards.

(4 + x) x (8 + x) = 60

x^{2} + 12x + 28 = 60

x^{2} + 12x - 32 = 0

(x + 14) = 0 or (x - 2) = 0

x = -14 or x =2

Thus, x = 2

The distance added to each dimension is 2 yards.

4 0
3 years ago
PLEASE HELP QUICK!! WILL OFFER 100 POINTS TO THE FIRST ONE THAT ANSWERS
Reil [10]

Given

x+1 = \sqrt{7x+15}

We have to set the restraint

x+1\geq 0 \iff x \geq -1

because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:

(x+1)^2=7x+15 \iff x^2+2x+1=7x+15 \iff x^2-5x-14 = 0

The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.

Similarly, we have

x-3 = \sqrt{x-1}+4 \iff x-7=\sqrt{x-1}

So, we have to impose

x-7\geq 0 \iff x \geq 7

Squaring both sides, we have

(x-7)^2=x-1 \iff x^2-14x+49=x-1 \iff x^2-15x+50 = 0

The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.

7 0
3 years ago
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