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3 years ago

Help plzzzzz ASAP PLZZZ

Mathematics

1 answer:

Marta_Voda [28]3 years ago

4 0

Positive 8 because subtracting a negative is the same as adding a positive

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0.2y=0.5x+0.1 please solve with math thank you

Cerrena [4.2K]

<span>"Simplifying 0.2y = 0.5x + 0.1
Reorder the terms: 0.2y = 0.1 + 0.5x Solving 0.2y = 0.1 + 0.5x Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Divide each side by '0.2'. y = 0.5 + 2.5x Simplifying y = 0.5 + 2.5x"</span>

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3 years ago

Which expression is equivalent to (cos x)(tan(–x))?

Naya [18.7K]

The tan(-x) is the same thing as -tan(x). The tangent function is also the same thing as sin(x)/cos(x), right? So let's rewrite that tan in terms of sin and cos:
$[cos(x)][tan(-x)]$ is the same as $[cos(x)][ -\frac{sin(x)}{cos(x)}]$
We can now cancel out the cos(x), which leaves us only with -sin(x) remaining. So your answer is A.

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3 years ago

Read 2 more answers

How tall is the towerr

skad [1K]

Answer:

if you're talking about eifell tower is 984′, 1,063′ to tip

Step-by-step explanation

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3 years ago

Round 827.3 to 3 significant figures

madreJ [45]

Answer:

To round to three significant figures, look at the fourth significant figure. It's a 5 , so round up.

To round to four significant figures, look at the fifth significant figure. It's a 1 , so round down.

To round to two significant figures, look at the third significant figure. It's an 8 , so round up.

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2 years ago

When fritz drives to work his trip takes 40 minutes, but when he takes the train it takes 30 minutes. find the distance fritz t

sweet-ann [11.9K]

Distance = rate*time

convert minutes to hour first because the question talking about 15 mile per hour
40 mins = 40/60 2/3 hrs
30 mins = 30/60 = 1/2hrs

Assume that s be the speed when Fritz driving, so
s + 15 will be the speed of the train.

We know the time we know the speed, Next
distance that Fritz drive = $\frac{2}{3}s$
distance the train travel = $\frac{1}{2}(s+15)$

The question: Assume that the train travels the same distance as the car
==> $\frac{2}{3}s = \frac{1}{2}(s+15)$
==> $\frac{2}{3}s = \frac{1}{2}s + \frac{15}{2}$
==> $\frac{2}{3}s - \frac{1}{2}s = \frac{15}{2}$
==> $\frac{1}{6}s = \frac{15}{2}$
==> $\frac{6}{1} * \frac{1}{6}s = \frac{15}{2} * \frac{6}{1}$
==> $s = 45$
Now we know that Fritz drive at 45 mph,
distance = $\frac{2}{3} * 45 = 30 miles$

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3 years ago