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vladimir1956 [14]
3 years ago
7

There are 27 players in a ping-pong tournament. each player plays every other player exactly once. how many games will be played

?
Mathematics
1 answer:
WINSTONCH [101]3 years ago
6 0
If x people play each other in pairs exactly once, then there will be
hmm

if 1, then 0 games
if 2, then 1 game
if 3 then 3 games ab, ac, bc
if 4 then ab, ac, ad, bc, bd, cd then 6 games
if 5 then ab, ac, ad, ae, bc, bd, be, cd, ce, de
we see a pattern
summation
first term is 0, when n=1
increases by 1
so
S_n=\frac{n(0+n-1)}{2} simlified to
S_n=\frac{n(n-1)}{2}

for n games, a total of \frac{n(n-1)}{2} games are played

for 27 players, there are a total of \frac{27(27-1)}{2}=\frac{27(26)}{2}= 27(13)=351 games
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