Complete Question
A satellite in geostationary orbit is used to transmit data via electromagnetic radiation. The satellite is at a height of 35,000 km above the surface of the earth, and we assume it has an isotropic power output of 1 kW (although, in practice, satellite antennas transmit signals that are less powerful but more directional).
Reception devices pick up the variation in the electric field vector of the electromagnetic wave sent out by the satellite. Given the satellite specifications listed in the problem introduction, what is the amplitude E0 of the electric field vector of the satellite broadcast as measured at the surface of the earth? Use ϵ0=8.85×10^−12C/(V⋅m) for the permittivity of space and c=3.00×10^8m/s for the speed of light.
Answer:
The electric field vector of the satellite broadcast as measured at the surface of the earth is 
Explanation:
From the question we are told that
The height of the satellite is 
The power output of the satellite is 
Generally the intensity of the electromagnetic radiation of the satellite at the surface of the earth is mathematically represented as

substituting values


This intensity of the electromagnetic radiation of the satellite at the surface of the earth can also be mathematically represented as

Where
is the amplitude of the electric field vector of the satellite broadcast so

substituting values


Earth is smaller and have 1 moon so it rotates faster than jupiter and it have 6 moons
Also,earth is the earth is the earth and orbits the sun faster than jupiter the 7th
Answer:
Hello
A. The muscle contracts causing the tendon to pull the bone.
The highest frequency (f) at which the source can operate is given as:
f = 55.133Hz.
<h3>What are sinusoidal waves?</h3>
The most realistic representation of how many objects in nature change state is a sine wave or sinusoidal wave.
A sine wave depicts how the intensity of a variable varies over time.
<h3>What is the calculation justifying the above result?</h3>
P = (1/2) μω²A²v
300W = 1/2 (4 X 10⁻²kg/m) ω₂ (0.05m)²v
Thus the wave speed is:
v = √(T/μ)
= √[(100N)/(4 X 10⁻²kg/m)
= 50m/s
300W = 1/2(4 X 10⁻²kg/m) ω²(0.05m)² (50m/s)
⇒ ω = 346.41 1/s
ω = 346.41 1/s
= 2πf
⇒ f = 55.133Hz
Learn more about Sinusoidal waves:
brainly.com/question/20912200
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