Answer:
The required proof is shown below.
Step-by-step explanation:
Consider the provided figure.
It is given that KM=LN
We need to prove KL=MN
Now consider the provided statement.
KM = LN Given
KM = KL+LM Segment addition postulate
LN = LM+MN Segment addition postulate
KL+LM = LM+MN Substitution property of equality
KL = MN Subtraction property of equality
The required proof is shown above.
parallel lines have the same slope
The slope-intercept form of a linear equatio is y=mx+b, where m stands for the "slope of the line" and b stands for the "y-intercept of the line"
They give you the equation y= -5/6x+3 Notice this is already on the slope-intercept form, so in this case the slope is -5/6 and the y-intercept is 3
You want an equation of the line that is parallel to the given line. The slopes must be the same, so m=-5/6
So far we have y=-5/6x + b
We don't have b yet but that can be found using the given point (6,-1) which tells you that "x is 6 when y is -1"
Replace that on the equation y=-5/6x + b and you get
-1 = (-5/6)(6) + b
-1 = -5 +b
4 = b
b = 4
We found b, or the y-intercept
Go back to the equation y = -5/6 x + b and replace this b with the b we just found
y = -5/6x + 4
Answer:
0.284
Step-by-step explanation:
To carry out this calculation, we begin by describing the sampling distribution of the sample proportion.
The sample size is n = 50 and the population proportion of teachers who made an apparel purchase is 0.56.
Shape: Because np = (50)(0.56) = 28 and n(1 – p) = (50)(0.44) = 22 are both at least 10, the shape of the sampling distribution of the sample proportion is approximately Normal.
Center:
μ
p
^
=
p
=
0
.
5
6
μ
p
^
=p=0.56
Variability: The standard deviation of the sample proportion is approximately
(
0
.
5
6
)
(
0
.
4
4
)
5
0
≈
0
.
0
7
0
2
50
(0.56)(0.44)
≈0.0702.
P(
p
^
p
^
> 0.6) = Normalcdf(lower: 0.6, upper: 1000, mean: 0.56, SD: 0.0702) = 0.284.
P
(
p
^
>
0
.
6
)
=
P
(
z
>
0
.
6
−
0
.
5
6
0
.
0
7
0
2
)
=
P
(
z
>
0
.
5
7
)
=
1
−
0
.
7
1
5
7
=
0
.
2
8
4
3
P(
p
^
>0.6)=P(z>
0.0702
0.6−0.56
)=P(z>0.57)=1−0.7157=0.2843
I believe it’s 20 m just took the test
Amount = 100000(1 + 0.04)^20 = 100000(1.04)^20 = $219,112.31
Compound Interest = $219,112.31 - $100,000 = $119,112.31
