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fomenos
3 years ago
12

We can sort a given set of n numbers by first building a binary search tree containing these numbers (using Tree-Insert repeated

ly to insert the numbers one by one) and then printing the numbers by an inorder tree walk. What are the worst-case and best-case running times for this sorting algorithm?

Computers and Technology
1 answer:
OLga [1]3 years ago
5 0

Worst case for binary search tree -O(n)

Best case for binary search tree -O(1)

<u>Explanation:</u>

The Binary search tree is the special type of binary tree. There are two child node

  1. Left child node
  2. Right child node  
  • In that, the right child node has a value greater than it’s the parent node. The left child node has value less than it’s the parent node.
  • In the below fig. for inserting element 0, it must be inserted as the left child of 1. Therefore, for sorting we have traveled in reverse order from (3,2,1) this is the worst-case complexity O(n).

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Consider the following program segment. ifstream inFile; //Line 1 int x, y; //Line 2 ... //Line 3 inFile &gt;&gt; x &gt;&gt; y;
MrMuchimi

Answer:

inFile.open("progdata.dat");

Explanation:

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3 years ago
Hey! I was recommended a site “9anime” the other day. All’s been going well but I accidentally taped on a new dub settingZ somet
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2 years ago
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4 0
3 years ago
Write a SELECT statement that returns one row for each customer that has orders with these columns:
d1i1m1o1n [39]

Answer:

SELECT email_address,

SUM(item_price * Quantity) AS item_price_total,

SUM(discount_amount * Quantity) AS discount_amount_total

FROM Customers c

JOIN Orders o ON c.CustomerID = o.CustomerID

JOIN Order_Items oi ON o.OrderID = oi.OrderID

GROUP BY email_address

ORDER BY item_price_total DESC

Explanation:

In this SQL statement the SELECT statement selects the following columns:

email_address

item_price

Quantity

discount_amount

There are two tables Customers and Order_Items

SUM aggregate function is used to add the values of the product of the columns discount_amount and Quantity. It is also used to get the sum of the product of two columns discount_amount and Quantity.

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JOIN is used here to join the columns from the tables Order_items and Customers.

GROUP BY is used to group the result of rows and is used with functions like SUM. Here the rows are grouped by the email address.

ORDER BY is used to order the result. Here the result is ordered by item_price_total in descending  order.

This SELECT statement can also be written as following:

SELECT c.email_address,

SUM(o.item_price * o.Quantity),

SUM(o.discount_amount * o.quantity)

FROM customer c

JOIN Order_Items o ON o.id = c.id

GROUP BY c.email_address

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4 years ago
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Answer:

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end

end

AdjustOutput(20, 15, 149)

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3 years ago
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