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elixir [45]
3 years ago
14

Write a loop that reads strings from standard input where the string is either "land", "air", or "water". The loop terminates wh

en "xxxxx" (five x characters) is read in. Other strings are ignored. After the loop, your code should print out 3 lines: the first consisting of the string "land:" followed by the number of "land" strings read in, the second consisting of the string "air:" followed by the number of "air" strings read in, and the third consisting of the string "water:" followed by the number of "water" strings read in. Each of these should be printed on a separate line. Use the up or down arrow keys to change the height.
Computers and Technology
1 answer:
____ [38]3 years ago
4 0

Answer:

count_land = count_air = count_water = 0

while True:

   s = input("Enter a string: ")

   if s == "xxxxx":

       break

   else:

       if s == "land":

           count_land += 1

       elif s == "air":

           count_air += 1

       elif s == "water":

           count_water += 1

print("land: " + str(count_land))

print("air: " + str(count_air))

print("water: " + str(count_water))

Explanation:

*The code is in Python

Initialize the variables

Create a while loop that iterates until a specific condition is met. Inside the loop, ask the user to enter the string. If it is "xxxxx", stop the loop. Otherwise, check if it is "land", "air", or "water". If it is one of the given strings, increment its counter by 1

When the loop is done, print the number of strings entered in the required format

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Answer:

1: #include <iostream>

2: using namespace std;

3: int main()

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11: cin>>c;

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15: int bottom = b*d;

16: cout<<"Sum: "<<top<<"/"<<bottom<<"\n";

17: top = (a*d)-(b*c);

18: cout<<"Difference: "<<top<<"/"<<bottom<<"\n";

19: top = a*c;

20: cout<<"Product: "<<top<<"/"<<bottom<<"\n";

21: top = a*d;

22: bottom = b*c;

23: cout<<"Quotient: "<<top<<"/"<<bottom<<"\n";

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Explanation:

The Program is written in C++ programming language

The Program is left numbered

Line 5 was used for variable declaration.

Variables a,b represents the numerator and denominator of the first fraction

While variables c,d represent the numerator and denominator of the second fraction

Line 6 prints "n1" without the quotes which represents the numerator of the first fraction

Line 7 accepts input for the numerator of the first fraction.

Line 8 prints "d1" without the quotes which represents the denominator of the first fraction

Line 9 accepts input for the denominator of the first fraction.

Line 10 prints "n2" without the quotes which represents the numerator of the second fraction

Line 11 accepts input for the numerator of the second fraction.

Line 12 prints "d2" without the quotes which represents the denominator of the second fraction

Line 13 accepts input for the denominator of the second fraction.

Line 14 and 15 calculate the sum of the fractions which is then printed on line 16

Line 17 calculates the difference of the fractions which is then printed on line 18

Line 19 calculates the product of the fractions which is then printed on line 20

Line 21 and 22 calculates the quotient of the fractions which is then printed on line 23

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The answer is C. Central processing unit (or CPU).

The trick is in the name, central processing unit :)

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