Try this solution:
1. In order to built the line required in the condition it need to determine its equation.
Using the coordinates of point B (5;2), if to substitute them into the given equation: 2=-3*5+b, ⇒ b=17. It means, that the equation of the line required in the condition is y= -3x+17.
2. The graph is in the attachment; point (0;17) is the intersection point of Y-axis and the line.
I am pritty shure i dont know
I think it would be (15-6)*5 because when it says 5 times you would cross out both B and D but then you have to find out what large as 15 minus 6 which i think would be (15-6) so your answer would be C. (15-6)*5
Answer:
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Step-by-step explanation:
30y
Answer:
0.09
Step-by-step explanation:
Given :
P(bike) = 0.8
P(car) = 0.2
P(Late given car) = P(Late | car) = 0.05
P(Late given bike) = p(Late | bike) = 0.1
Probability that professor is late :
P(late) = [P(Late | car) * p(car)] + [p(Late | bike) * p(bike)]
P(late) = [0.05 * 0.2] + [0.1 * 0.8]
P(late) = 0.01 + 0.08
P(late) = 0.09
