An <u>example of a problem</u> where I <em>would not</em> group the addends differently is:
3+2+4.
An <u>example of a problem</u> where I <em>would</em> group the addends differently is:
2+5+8.
Explanation:
In the <u>first problem</u>, I would not group the addends differently before adding. This is because I cannot make 5 or 10 out of any of the numbers. We group addends together to make "easier" numbers for us to add, such as 5 and 10. If we cannot do that, there is no reason to regroup the addends.
In the <u>second problem</u>, I would regroup like this:
2+8+5
This is because 2+8=10, which makes the problem "easier" for us to add. Since we can get a number like this that shortens the process, we can regroup the addends.
Yfiyfidy. It’s soot ioydotdi
It’s Bc. H. Dey h. Yes so I’m hehe what crazy now
Answer:
y is equal to 65 so 115 isn't a possible answer
Answer:
D.
Step-by-step explanation:
The solution is where the lines intersect which is at the point (3,2).
So the answer is Option D.
The point (3,2) satisfies both equations.
