Answer:
a. autotriploid of species A: 63 chromosomes
b. autotetraploid of species B: 96 chromosomes
c. allotriploid from species A and B: 1) 66 chromosomes and 2) 69 chromosomes
Explanation:
<u>For a.</u>
this species will have 3 haploid sets of chromosomes ('tri' means 3)
one haploid set = 21
21 × 3 = 63 chromosomes
<u>For b.</u>
this species will have 4 haploid sets of chromosomes ('tetra' means 4)
one haploid set = 24
24 × 4 = 96 chromosomes
<u>For c.</u>
there are two ways to do this:
1) two sets of chromosomes from species A and one from species B
42 + 24 = 66 chromosomes
2) one set of chromosomes from species A and two from species B
21 + 48 = 69 chromosomes
Hope that answers the question, have a great day!
The A antibodies will produce A antibodies and the B antibodies will produce B antibodies
Answer:
10 arrangements, although the parents have brown hair, they have a recessive allele for the blonde hair. The two brown heads can make a blonde or brown and or course even a red haired child. In this case the parents with dominant brown hair have a recessive blonde hair giving them a chance to have 10 arrangements to have blonde hair due to their recessive allele.
Explanation:
Heterozygous means that to have inherited different forms of a particular gene from each parent. In this case the children will inherit both brown and blonde hair genes.
A combination of two or more metals is called and Alloy.
Answer:
Magnesium is in Group II and has two electrons in its valence shell. Thus it tends to lose two electrons. It wants to be a stable and it is easier for it to lose two electrons than gain 6.
Explanation:
