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Andreas93 [3]
3 years ago
12

I didnt understand this question . could someone help me ?​

Physics
1 answer:
Vikki [24]3 years ago
4 0

Explanation:

decelation =5m/s

u=25m/s

v=0m/s

t=?

then;a=(v-u)/t

t=(v-u)/a

but decelation is negative of acceleration

t=(0-25)/-5

t=5s

to find distance

s=ut+1/2at^2

s=25*5+1/2(-5)5^2

s=62.5m

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Two identical cans, one filled with lead shot and the other with feathers, are dropped from the same height by a student standin
Serga [27]

Answer:

<em></em>

<em>The lead shot-filled can experiences a greater force due to gravity because it contains more mass.</em>

Explanation:

The gravitational attractive force that acts on two different bodies on Earth depends on the body's masses. The greater the mass, the stronger the force of gravity acts on the body. The smaller the mass, the weaker the force of gravity acts on the body.

The can with the lead shot in it has a greater mass than that of the can that is filled with feathers. Therefore,<em> the can with the lead shot will experience a greater force due to gravitational attraction of the Earth</em> than that of the can that is filled with feathers.

5 0
3 years ago
¿Cuál será la potencia o consumo en watt de una ampolleta conectada a una red de energía eléctrica doméstica monofásica de 220 v
g100num [7]

Answer:

La potencia o consumo en watt de una ampolleta conectada a una red de energía eléctrica doméstica monofásica de 220 volt, si la corriente que circula por el circuito de la ampolleta es de 0.45 ampere, es 99 Watts.

Explanation:

Potencia es la velocidad o rapidez con la que se consume la energía. Siendo la energía la capacidad que tiene un mecanismo o dispositivo eléctrico cualquiera para realizar un trabajo, también se puede definir potencia como la energía desarrollada o consumida en una unidad de tiempo. Su unidad de medida es el Watt.

La ley de Watt establece que la potencia eléctrica P suministrada por un elemento de circuito, es directamente proporcional al producto entre la tensión de la alimentación V del circuito y la intensidad de corriente I que circula por él.  

Matemáticamente, la ley de Watt se expresa:

P = V.I

donde V es medida en Volt e I es medida en Ampere.

En este caso:

  • V=220 volt
  • I= 0.45 ampere

Reemplazando:

P= 220 volt* 0.45 ampere

P= 99 Watts

<u><em>La potencia o consumo en watt de una ampolleta conectada a una red de energía eléctrica doméstica monofásica de 220 volt, si la corriente que circula por el circuito de la ampolleta es de 0.45 ampere, es 99 Watts.</em></u>

3 0
3 years ago
- 3000 J of work is done on a 2kg object over a distance of 10m. What is the force acting on the object?
SpyIntel [72]
The answer is B. 300N
7 0
3 years ago
A 2.7 kg ball is thrown upward with an initial speed of 20.0 m/s from the edge of a 45.0-m-high cliff. At the instant the ball i
madam [21]

Answer:

(a) At what angle above the horizontal should the ball be thrown so that the runner will catch it  just before it hits the ground? (b) How far does the woman run before she catches the ball?

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(b) = 33.4 m

Explanation:

see the attached file below

4 0
3 years ago
A 70-kg pole vaulter running at 11 m/s vaults over the bar. Her speed when she is above the bar is 1.3 m/s. Neglect air resistan
yKpoI14uk [10]

Answer:

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The expression is simplified and final height is cleared within the equation:

\frac{1}{2}\cdot (v_{A}^{2} - v_{B}^{2}) = g\cdot h_{B}

h_{B} = \frac{(v_{A}^{2}-v_{B}^{2})}{2\cdot g}

h_{B} = \frac{[(11\,\frac{m}{s} )^{2}-(1.3\,\frac{m}{s} )^{2}]}{2\cdot (9.807\,\frac{m}{s^{2}} )}

h_{B} = 6.083\,m

5 0
3 years ago
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