The illustration shows a light ray striking an object.

What is the dimensional formula of thermal conductivity?

Inga [223]

Answer:

The dimension of thermal conductivity is M1L1T−3Θ−1, expressed in terms of the dimensions mass (M), length (L), time (T), and temperature (Θ). Other units which are closely related to the thermal conductivity are in common use in the construction and textile industries.

Explanation:looked it up for ya

6 0

3 years ago

The rate at which correct flows is measured in _?

Reika [66]

C. amperes

this what i think it is

6 0

3 years ago

A 7.00-kg object accelerates from rest to a final velocity in 55 seconds. If the magnitude of the

Len [333]

Answer:

The final velocity of the object is 330 m/s.

Explanation:

To solve this problem, we first must find the acceleration of the object. We can do this using Newton's Second Law, given by the following equation:

F = ma

If we plug in the values that we are given in the problem, we get:

42 = 7 (a)

To solve for a, we simply divide both sides of the equation by 7.

42/7 = 7a/7

a = 6 m/s^2

Next, we should write out all of the information we have and what we are looking for.

a = 6 m/s^2

v1 = 0 m/s

t = 55 s

v2 = ?

We can use a kinematic equation to solve this problem. We should use:

v2 = v1 + at

If we plug in the values listed above, we should get:

v2 = 0 + (6)(55)

Next, we should solve the problem by performing the multiplication on the right side of the equation.

v2 = 330 m/s

Therefore, the final velocity reached by the object is 330 m/s.

Hope this helps!

7 0

4 years ago

A horizontal metal bar oriented east-west drops straight down in a location where the earth's magnetic field is due north. as a

amid [387]

Metal bar is aligned along East- West direction and it is dropped vertically down

So its velocity is along -Z direction,

Now the Earth's magnetic field is towards north so its towards +Y direction

now we have formula for force on a moving charge

$F = q(v X B)$

v = - z direction

B = + y direction

now by the above formula

$F = q(v(-k) X B(j))$

$F = qvB (i)$

So force is towards East

so all positive charge is towards East end

5 0

3 years ago

In the first stage of a two-stage rocket, the rocket is fired from the launch pad starting from rest but with a constant acceler

AnnZ [28]

Answer:

3091.56

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s² (positive downward and negative upward)

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times 25+\frac{1}{2}\times 3.5\times 25^2\\\Rightarrow s=1093.75\ m$

Distance traveled in the first stage is 1093.75 m

$v=u+at\\\Rightarrow v=0+3.5\times 25\\\Rightarrow v=87.5\ m/s$

Velocity at the end of first stage is 87.5 m/s

$v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{132.5-87.5}{10}\\\Rightarrow a=4.5\ m/s^2$

Acceleration of the second stage is 4.5 m/s²

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=87.5\times 10+\frac{1}{2}\times 4.5\times 10^2\\\Rightarrow s=1100\ m$

Distance traveled in the second stage is 1100 m

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-132.5^2}{2\times -9.81}\\\Rightarrow s=894.81\ m$

Distance traveled after the second stage has stopped firing is 894.81 m

Total height the rocket reached = 1093.75+1100+897.81 = 3091.56 m

3 0

4 years ago