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4 years ago

I need help on question 4!

Physics

1 answer:

alukav5142 [94]4 years ago

4 0

Answer:

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Alice and Bob sit on a see saw, that consists of a uniform beam of mass 20kg and a fulcrum rock, that acts as a pivot point. The

tankabanditka [31]

Answer:

Explanation:

Given

Mass of alice $M_a=50 kg$

Mass of bob $M_b=70 kg$

Mass of beam $M=20 kg$

Suppose fulcrum is at distance of d from bob thus From diagram

Equating torque i.e. torque of Bob,Alice and beam must cancel out each other to be balanced

$500\times (8-d)+20\times (4-d)=70\times d$

$400-50d+80-2d=70d$

$480=140d$

$d=\frac{480}{140}$

$d=3.43 m$

5 0

4 years ago

¿Qué distancia en metros recorre una persona en bicicleta, en 15 min, si lleva una velocidad constante de 12 m/s? (10 puntos)

melamori03 [73]

Answer:

Explanation:

6 0

3 years ago

The type of material that will easily accept the flow of electric current is called a(an) circuit. conductor. insulator. resisto

solong [7]

<span>electric current is easily accepted by a conductor.</span>

4 0

3 years ago

Read 2 more answers

How many revolutions will a car wheel of diameter 18 in. make as the car travels a distance of one mile? (Round your answer to t

MA_775_DIABLO [31]

The circumference of a circle is (pi) x (the diameter).

If the diameter of the wheel is 18 inches (1.5 feet), then its circumference is

(pi) x (1.5 feet) = 1.5π feet .

Every time the wheel rotates once, the car moves 1.5π feet.

1 mile = 5,280 feet

In order for the car to move 5,280 feet, the wheel has to rotate

(5,280 / 1.5π) times.

(5,280 / 1.5π) = 1,120.4508 times

Rounded to the nearest whole number: <em>1,120 revolutions</em>

3 0

3 years ago

A rod 10.0 cm long is uniformly charged and has a total charge of -21.0 µC. Determine the magnitude and direction of the electri

lesya692 [45]

Answer:

The magnitude of electric field is $2.3\times10^6\ C/m^2$ and the direction is inward.

Explanation:

Given that,

Length of rod = 10.0 cm

Charge $Q = -21.0\times10^{-6}\ C$

Distance D = (34.0-10) cm = 0.24 m

We need to calculate the electric field along the axis

$E=\dfrac{kQ}{D(D+L)}$

Where, Q = charge

D = distance

Put the value into the formula

$E = \dfrac{9\times10^{9}\times(-21\times10^{-6}}{0.24(0.24+0.10)}$

$E=-2.3\times10^6\ C/m^2$

Negative sign shows the direction of electric field is inward that means toward the center.

Hence, The magnitude of electric field is $2.3\times10^6\ C/m^2$ and the direction is inward.

6 0

3 years ago