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tigry1 [53]
3 years ago
14

A 2.7 kg ball is thrown upward with an initial speed of 20.0 m/s from the edge of a 45.0-m-high cliff. At the instant the ball i

s thrown, a woman starts running away from the base of the cliff with a constant speed of 6.00 m/s. The woman runs in a straight line on level ground. Ignore air resistance on the ball.

Physics
1 answer:
madam [21]3 years ago
4 0

Answer:

(a) At what angle above the horizontal should the ball be thrown so that the runner will catch it  just before it hits the ground? (b) How far does the woman run before she catches the ball?

(a) = 72.54°

   ≅ 72.5°

(b) = 33.4 m

Explanation:

see the attached file below

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Forces are never isolated because they come in... *
Fudgin [204]

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different shapes

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A mover loads a 100 kg box into the back of a moving truck by
NeX [460]

Answer:

2.7

Explanation:

The following data were obtained from the question:

Mass (m) of box = 100 Kg

Length (L) of ramp = 4 m

Height (H) of ramp = 1.5 m

Mechanical advantage (MA) of ramp =?

Mechanical advantage of a ramp is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is given by:

Mechanical Advantage = Lenght / height

MA= L/H

With the above formula, we can obtain the mechanical advantage of the ramp as follow:

Length (L) of ramp = 4 m

Height (H) of ramp = 1.5 m

Mechanical advantage (MA) of ramp =?

MA = 4/1.5

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3 0
3 years ago
The 4kg head of a sledge hammer is moving at 6m/s when it strikes a chisel, driving it into a log. The duration of the impact (o
LUCKY_DIMON [66]

Answer:

The average impact force is 12000 newtons.

Explanation:

By Impact Theorem we know that impact done by the sledge hammer on the chisel is equal to the change in the linear momentum of the former. The mathematical model that represents the situation is now described:

\bar F \cdot \Delta t = m \cdot  (v_{2}-v_{1}) (1)

Where:

\bar F - Average impact force, in newtons.

\Delta t - Duration of the impact, in seconds.

m - Mass of the sledge hammer, in kilograms.

v_{1}, v_{2} - Initial and final velocity, in meters per second.

If we know that \Delta t = 0.0020\,s, m = 4\,kg, v_{1} = -6\,\frac{m}{s} and v_{2} = 0\,\frac{m}{s}, then we estimate the average impact force is:

\bar F = \frac{m\cdot  (v_{2}-v_{1})}{\Delta t}

\bar F = 12000\,N

The average impact force is 12000 newtons.

5 0
3 years ago
Two poles are connected by a wire that is also connected to the ground. The first pole is 20ft tall and the second pole is 10ft
Natasha2012 [34]

Answer: 31.6ft

Explanation:

Check the attachment for the diagram.

According to the right angle triangle AEC, we will use Pythagoras theorem to get |AC|. Note that |AE| = |AB| - |CD|

that is 20ft - 10ft = 10ft

According to the theorem, the square of the sum of the adjacent side and the opposite side is equal to the square of the hypotenuse.

|AE|^2 + |EC|^2 = |AC|^2

10^2 + 30^2 = |AC|^2

100 + 900 = |AC|^2

|AC| = √1000

|AC| = 31.6ft

Therefore, the wire should be anchored 31.6ft to the ground to minimize the amount of wire needed.

6 0
4 years ago
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