Since U is a universal set where S is its subset, then set U should consist of all the letters, numbers and punctuation mark in a keyboard. In other words, universal set U consists of the following elements:
U = (0, 1, 2, 3, 4, 5, 6, 7, 8, 9)
U = (x| x comprised of all the letters in the alphabet fro a to z)
U = (!,.,,,?,!:,;,",',-)
For

,

, all the more

, therefore no solution.
For

, we have

. Obviously that' false.
For

both

and

, where

, belong to the range

, then

belong to the range

.
Those ranges don't have a common part, therefore, again, no solution.
So, the equation

doesn't have a solution.
Answer:
8
Step-by-step explanation:
To find the largest number of groups she can have, find the largest number that can divide 104 and 88 evenly.
This number is 8, since 8 divides 104 to 13 and it divides 88 to 11.
This means each group will have 13 nickels and 11 dimes.
So, the answer is 8 groups.