Quadratic f(x) = (x -h)² +k has vertex (h, k) and axis of symmetry x=h. When k is negative, the number of real solutions is 2, because both branches of the function cross the x-axis.
In your equation, h = -3 and k = -8.
Axis of symmetry: x = -3
Vertex: (-3, -8)
Number of real solutions: 2
T= 60°
It is an equilateral triangle which means all sides and angles are equal
u= 10m
It is an equilateral triangle which means all sides and angles are the same
Answer:
could you include a pic please?
Answer:
e_3^{4} will be the exponential expression.
Step-by-step explanation:
We have to choose a number between 0 ad 10 and has to be odd to be base say 3
And even number between 0 ad 10 to be exponent say 4.
So the exponential expression will be : e_3^{4}
According to the information given above expression is the required expression.
Answer: y - 5 = 0(x - 1)
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Explanation:
Recall that point slope form in general is written as such
y - y1 = m(x - x1)
where,
m is the slope
(x1,y1) is the point the line goes through
The given equation y = 7 can be written as y = 0x+7. So we see that this line has a slope of m = 0
Plug m = 0 along with the given point (x1,y1) = (1,5) into the point slope equation and we get
y - y1 = m(x - x1)
y - 5 = 0(x - 1)
which is the final answer
note: the equation in bold can be rearranged and simplified to get y = 5; however your teacher seems to want the answer in point-slope form, so we leave it as such.
