9/4x -15 for x=4
To find this answer you must plug the 4 everywhere the x is located.
(9/4)(4) -15
Multiply 9/4 by 4
(9/4) x 4 = 9
Now we take our 9 answer and add it to -15.
9-15 = -6
The answer is -6
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For the other equation, you also must plug in 3 where ever x is located in the equation.
5/3x -3/5
(5/3)(3) -3/5
Multiply 5/3 and 3
(5/3) x 3 = 5
Take that answer of 5 and add -3/5
5- (3/5) =4 2/5
The answer to this equation would be 4 2/5 or 4.4
Answer:
The second expression is the product of the above expressions.....
<u>Given</u>:
Given that O is the center of the circle.
AB is tangent to the circle.
The measure of ∠AOB is 68° and we know that the tangent meets the circle at 90°
We need to determine the measure of ∠ABO.
<u>Measure of ∠ABO:</u>
The measure of ∠ABO can be determined using the triangle sum property.
Applying the property, we have;

Substituting the values, we get;

Adding the values, we have;

Subtracting both sides by 158, we get;

Thus, the measure of ∠ABO is 22°
Answer:11,256
Step-by-step explanation:
You forgot to say what the question actually is !
But I've seen this problem before, in the last few days, here on Brainly.
I think the problem has three parts: 1). Solve the equation for 'a';
2). Solve it for 'b'; and 3). Solve it for 'c'.
I'll slog through that, and I'll try to explain what I'm doing clearly enough
so that eventually, you can do it on your own ... which is really the whole
idea behind this website.
1). Solve the equation for 'a'. That means you have to wind up with something
that says a = everything else.
<u>D = (a + b + c) / c</u>
Split the right side into 3 fractions: D = a/c + b/c + c/c
But c/c =1 , so the equation says D = a/c + b/c + 1
Subtract (b/c +1) from each side: D - b/c - 1 = a/c
Multiply each side by 'c' : <em>Dc - b - c = a</em>
========================
2). Solve the equation for 'b'. That means you have to wind up with something
that says b = everything else.
<u>D = (a + b + c) / c</u>
Split the right side into 3 fractions: D = a/c + b/c + c/c
But c/c =1 , so the equation says D = a/c + b/c + 1
Subtract (a/c +1) from each side: D - a/c - 1 = b/c
Multiply each side by 'c' : <em>Dc - a - c = b</em>
==========================
3). Solve the equation for 'c'. That means you have to wind up with
something that says c = everything else.
<u>D = (a + b + c) / c</u>
Split the right side into 3 fractions: D = a/c + b/c + c/c
But c/c =1 , so the equation says D = a/c + b/c + 1
Subtract 1 from each side: D - 1 = a/c + b/c
The two fractions on the right can be added/combined: D - 1 = (a + b) / c
Multiply each side by 'c' : c(D - 1) = (a + b)
Divide each side by (D - 1) : <em>c = (a + b) / (D - 1)</em>