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lozanna [386]
4 years ago
13

Continuous data

Computers and Technology
1 answer:
Elena-2011 [213]4 years ago
7 0

Answer: Could be subdivided into smaller and smaller units.

Explanation:

 The continuous data are basically measured in the small units and can be easily subdivided into smaller parts without changing their actual meaning.

The continuous data also contain numeric value and can be divided into smaller and finer meaningful parts.

The continuous data can be measured according to the precision of the system. The size and volume are the example of the continuous data.

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Answer:

Explanation:

It is assumed that name and age have been declared suitably for storing names and ages. so the following is the code to read in a name  and age and printout the message "the age of name is age. "

cin >> Name;

cin >> Age;

cout << "The age of " << Name << " is " << Age << ".";

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Which of the following tasks would a database administrator perform ? A identify computer security photos, B. Make sure protocol
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Choose ALL guidelines listed below pertaining to fair use.
tino4ka555 [31]

Answer:

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In this lesson, you'll learn about the copyright protections that apply to work posted online. You'll learn about the rules that determine which images and text you can use, and how you can use them. You'll also learn how to protect the content you create.

The laws discussed in this lesson are United States laws. No lawyer was involved in preparing this lesson. We are not legal experts, and this lesson should not be taken as legal advice.

Understanding copyright

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3 years ago
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Which is a benefit of owning a desktop computer instead of a laptop?
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4 years ago
Read 2 more answers
A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st
Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0
3 years ago
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