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sveta [45]
2 years ago
8

What percentage of the semi circle is shaded? ​

Mathematics
1 answer:
mezya [45]2 years ago
3 0

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%

r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\% (1)

Where:

  • A_{h} - Area of the half cross, in square centimeters.
  • A_{s} - Area of the semicircle, in square centimeters.
  • r - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100

r \approx 23.606\,\%

The percentage of the semicircle shaded section is approximately 23,606 %.

We kindly invite to check this question on percentages: brainly.com/question/15469506

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igor_vitrenko [27]

Answer:

28.25 square units

Step-by-step explanation:

A circumference of the circle is

C=2\pi r,

where r is the radius of the circle.

So,

18.84=2\pi r\\ \\r=\dfrac{18.84}{2\pi}=\dfrac{9.42}{\pi}\ cm

The area of the circle is

A=\pi r^2

Substitute the value of the radius:

A=\pi \cdot \left(\dfrac{9.42}{\pi}\right)^2=\dfrac{9.42^2}{\pi}\approx 28.25\ un^2

8 0
3 years ago
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lyudmila [28]

Answer: D

Step-by-step explanation:

8 0
2 years ago
I now have another question to ask.
marissa [1.9K]

Answer:

23.6 ft

Step-by-step explanation:

Sketch a right triangle representing this situation.  The length of the hypotenuse is 26 ft and the angle of elevation from ground to top of ladder is 65°.  The "opposite side" is the reach of the ladder, which we'll call x.

Then:

                        opp

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or (26 ft)(sin 65°) = opp side = height off the ground of top of ladder.

Evaluating this, we get:

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3 years ago
School started at 8:05 a.m. and ended at 2:40 p.m. The work below shows Erica’s calculation of the length of the school day.
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2 years ago
How do you solve this problem? (x+3) cubed
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we can use binomial theorem or pascal's triangle
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so
for the 3rd power
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7 0
3 years ago
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