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Marysya12 [62]
3 years ago
12

Which missing item would complete this beta decay reaction?

Physics
1 answer:
Flauer [41]3 years ago
8 0
For us to understand the missing item that would complete beta decay reaction, we need to achieve in depth understanding of chemical formulas and nuclear symbols. Next is to have great comprehension of the following points:
<span>1.) Neutron in nucleus breaks down and changes into a proton.
2) Then it emits an electron, as well as an anti-neutrino which go into space.
3) Lastly, atomic number continuously goes UP while mass number remains unchanged.</span>
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The pressure in a water line is 1500 kpa. what is the line pressure in (a) lb/ft2 units and (b) lbf/in2 (psi) units?
kotegsom [21]

To solve this problem, we know that:

1 psi = 6894.76 Pa

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Therefore:

a. 1500 x 10^3 Pa * (1 lb / ft^2 / 47.88 Pa) = 31,328.32 lb / ft^2

 

b. 1500 x 10^3 Pa * (1 psi / 6894.76 Pa) = 217.56 psi

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3 years ago
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Neptune has a mass that is about 17 times the mass of Earth. The distance between the Sun and Neptune is about 30.1 times the di
marshall27 [118]

Answer: 0.0187 times the force between Sun and Earth.

The gravitational force between two massive bodies is directly proportional to their masses and inversely proportional to the square of distance between them.

F=G\frac {M_1M_2}{d^2}

where G is the gravitational constant.

Let,

The mass of the Sun be M_S

The mass of the Earth beM_E

The mass of the Neptune beM_N

The Distance between Sun and Earth be d_{SE}

The Distance between Sun and Neptune be d_{NE}

It is given that the mass of Neptune is 17 times mass of Earth.

\Rightarrow M_N=17M_E

The distance of Neptune from Sun is 30.1 times the distance of Earth from Sun.

\Rightarrow D_{SN}=30.1D_{SE}

The Force between Earth and Sun is F_{SE}=3.5\times10^{28}N

The Force between Neptune and Sun:

F_{SN}=G\frac{M_SM_N}{D_{SN}^2}=G\frac{M_S17M_E}{(30.1D_{SE})^2}=\frac {17}{30.1^2}G\frac{M_SM_E}{D_{SE}^2}=\frac {17}{30.1^2}F_{SE}=0.0187F_{SE}


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A resistor of 4 ohms is connected isn series to a box speaker of unknown resistance.If a current of 0.6A flows through the speak
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Answer:

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