3 years ago

A vector is In English

Physics

1 answer:

zzz [600]3 years ago

3 0

A vector is a quantity or phenomenon that has two independent properties: magnitude and direction.

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A person is going to take a trip from town eight to town D to do this they travel 60 KM in .45 hour And then stop in town before

ANEK [815]

Answer:

v = 72 km / h

Explanation:

The definition of average speed is the distance traveled between the time interval

v = Δx / Δt

let's find the distance traveled

x = 60 + 30

x = 90 km

time spent, all time must be included, travel time and when stopped

t = 0.45 + 0.15 + 0.5+ 0.15

t = 1.25 h

we substitute in the initial equation

v = 90 / 1.25

v = 72 km / h

in going from one city to the other

4 0

3 years ago

If it takes 100 N to get a 10 kg object to accelerate at 10m/s/s, how much force will it take to get a 20 kg object to accelerat

yan [13]

Answer: C) 200 N

Explanation:

The force $F$ is defined as:

$F=m.a$

Where:

$m=20 kg$ is the mass of the object

$a=10 m/s^{2}$ is the acceleration

Then:

$F=(20 kg)(10 m/s^{2})$

Finally:

$F=200 N$

Hence, the correct option is C.

7 0

3 years ago

Why houses have garage?

kykrilka [37]

To keep cars safe...............

3 0

3 years ago

Read 2 more answers

Consider two transformers. Transformer A has 300 turns on its primary and 500 turns on its secondary. Transformer B has 250 turn

rusak2 [61]

Answer:

Secondary voltage on second transformer is 200 volt.

Explanation:

It is given two transformer

Let us consider first transformer.

Number of turns in primary $N_p=300$

Numb er of turns in secondary $N_s=500$

Now consider second transformer

Number of turns in primary $N_p=250$

Number of turns in secondary $N_s=1000$

Now it is given that same voltage of 50 volt is applied to primary of both the transformer.

For second transformer

$\frac{N_p}{N_s}=\frac{V_p}{V_s}$

$\frac{250}{1000}=\frac{50}{V_s}$

$V_s=200volt$

So secondary voltage on second transformer is 200 volt

4 0

4 years ago

A particle of mass 6.3 x 10-8kg and charge 7.1 muC is traveling due east. It enters perpendicularly a magnetic field whose magni

ASHA 777 [7]

Answer:

t=0.016s

Explanation:

we can use

$\frac{v}{r}=\omega=\frac{qB}{m}=\frac{7.1*10^{-6}C*1.7T}{6.3*10^{-8}kg}=191.58s^{-1}$

the time that the particle is in the magnetic field is one half oa period. Hence

$t=\frac{T}{2}=\frac{\pi}{\omega}=0.016s$

I hope this is useful for you

regards

8 0

3 years ago