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Verizon [17]
4 years ago
9

Which statement shows how to correctly convert from the mass of a compound in grams to the amount of that compound in moles?

Physics
1 answer:
expeople1 [14]4 years ago
6 0

Answer:

mass (grams) x 1 =

molar mass (g/mol)

amount (moles)

Explanation:

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The charge will be 3+
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Which of the following happens to an object in uniform circular motion?
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Answer:

As an object moves in a circle, it is constantly changing its direction. ... Accelerating objects are objects which are changing their velocity - either the speed (i.e., magnitude of the velocity vector) or the direction. An object undergoing uniform circular motion is moving with a constant speed.

5 0
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II) A 0.40-kg ball, attached to the end of a horizontal ord, is rotated in a circle of radius 1.3 m on a friction- less horizont
Lostsunrise [7]

Hi there!

In this instance, the object spinning in a horizontal circle will experience a net force in the horizontal direction due to tension.

The net force is equivalent to the centripetal force, so:

∑F = T

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v = √rT/m

v = 13.96 m/s

3 0
3 years ago
Two climbers are on a mountain. Simon, of mass m, is sitting on a snow covered slope that makes an angle θ with the horizontal.
elena-14-01-66 [18.8K]

Answer:

Explanation:

It is required that the weight of Joe must prevent Simon from being pulled down . That means he is not slipping down but tends to be towed down . So in equilibrium , force of friction will act in upward direction on Simon.

Let in equilibrium , tension in rope be T

For balancing Joe

T = M g

For balancing Simon

friction + T = mgsinθ

μmgcosθ+T = mgsinθ

μmgcosθ+Mg = mgsinθ

M = (msinθ - μmcosθ)

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5 0
3 years ago
A piece of taffy slams into and sticks to another identical piece of taffy that is at rest. The momentum of the two pieces stuck
-Dominant- [34]

Answer:

C. 50%

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Lets consider that the mass of taffy is m and its initial velocity is u and final velocity is v. Momentum is conserved so we can write it as,

mu = 2mv\\v = \frac{u}{2} \\

The initial kinetic energy = \frac{mu^{2} }{2}

As the Kinetic energy partly converted into heat.

The final kinetic energy = \frac{m(\frac{u}{2})^{2}  }{2} = \frac{mu^{2} }{4}

Change in the kinetic energy = \frac{mu^{2} }{2} - \frac{mu^{2} }{4} = \frac{mu^{2} }{4}

now we can determine the fraction of kinetic energy that has turned into heat

                           = \frac{Heat energy}{initial K.E} = \frac{\frac{mu^{2} }{4} }{\frac{mu^{2} }{2} }  = 1/2

                           = 50%

3 0
4 years ago
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