Answer:
since they have got specific and special metallic and non metallic characteristics I guess
Answer:
The direction of force is along negative Z axis and the magnitude of force is
6.4 x 10^-14 N.
Explanation:
q = - 1.6 x 10^-19 c
vx = 5 x 10^5 m/s, vy = 3 x 10^5 m/s, B = 0.8 T along Y axis
The velocity vector is given by
v = 5 x 10^5 i + 3 x 10^5 j
B = 0.8 j
Force on a charged particle place in a magnetic field is given by
F = q (v x B)
F = -1.6 x 10^-19 {(5 x 10^5 i + 3 x 10^5 j) x (0.8 j)}
F = - 1.6 x 10^-19 (5 x 0.8 x 10^5 k)
F = - 6.4 x 10^-14 k
The direction of force is along negative Z axis and the magnitude of force is
6.4 x 10^-14 N.
Answer:
Friction
Explanation:
Friction is a force that slows down moving objects. If you roll a ball across a shaggy rug, you can see that there are lumps and bumps in the rug that make the ball slow down. The rubbing, or friction, between the ball and the rug is what makes the ball stop rolling. External Force is required.
Answer:
His journey took him 3 hours 15 minutes.
Explanation: 4 miles every hour. So 1 hr is equal to 4 miles, 2 hrs is equal to 8 miles, 3 hrs is equal to 12 miles. Now he just has 1 miles left, and since it takes him a hour to cycle 4 miles, 60 divided by 4 is 15. Therefore, 1 mile is equal to 15 minutes.
Answer:
Explanation:
Given:
Length of cylinder is, L = 0.27 m
Outer radius of cylinder is, r_out = 1.12×10^{-2} m
Inner radius of cylinder is, r_in = 3.9×10^{-3} m
Mass of person, m = 60 kg
Young's modulus , Y = 9.4×10^9 N/m2
(a)
Compressional strain of humerous is,
![= \frac{(60 kg)(9.8 m/s2 )}{(\pi)[( 1.12\times 10^{-2})^2 - (3.9\times 10^{-3} m)^2] (9.4\times 10^9 N/m2 )}[tex] [tex]= 1.80\times 10^{-4} m](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B%2860%20kg%29%289.8%20m%2Fs2%20%29%7D%7B%28%5Cpi%29%5B%28%201.12%5Ctimes%2010%5E%7B-2%7D%29%5E2%20-%20%283.9%5Ctimes%2010%5E%7B-3%7D%20m%29%5E2%5D%20%289.4%5Ctimes%2010%5E9%20N%2Fm2%20%29%7D%5Btex%5D%3C%2Fp%3E%3Cp%3E%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%20%5Btex%5D%3D%201.80%5Ctimes%2010%5E%7B-4%7D%20m)
(b) Let assume that humerous is compressed by ΔL
Since, strain = ΔL/L0
Thus,
