Answer:
The answer is below
Step-by-step explanation:
Let S denote syntax errors and L denote logic errors.
Given that P(S) = 36% = 0.36, P(L) = 47% = 0.47, P(S ∪ L) = 56% = 0.56
a) The probability a program contains both error types = P(S ∩ L)
The probability that the programs contains only syntax error = P(S ∩ L') = P(S ∪ L) - P(L) = 56% - 47% = 9%
The probability that the programs contains only logic error = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
P(S ∩ L) = P(S ∪ L) - [P(S ∩ L') + P(S' ∩ L)] =56% - (9% + 20%) = 56% - 29% = 27%
b) Probability a program contains neither error type= P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
c) The probability a program has logic errors, but not syntax errors = P(S' ∩ L) = P(S ∪ L) - P(S) = 56% - 36% = 20%
d) The probability a program either has no syntax errors or has no logic errors = P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44
Answer:
12: 144
Step-by-step explanation:
As it fits all requirments.
Answer: Its a little blurry I cant se
Step-by-step explanation:
Answer: 
Step-by-step explanation:
Given
Survey shows that 16% of college students have dogs and 38% have HBO subscription
Probability that a random person have both is
![\Rightarrow P_o=0.16\times 0.38\quad [\text{As both events are independent}]\\\Rightarrow P_o=0.0608](https://tex.z-dn.net/?f=%5CRightarrow%20P_o%3D0.16%5Ctimes%200.38%5Cquad%20%5B%5Ctext%7BAs%20both%20events%20are%20independent%7D%5D%5C%5C%5CRightarrow%20P_o%3D0.0608)
The probability that the random person has neither of the two is
