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il63 [147K]
3 years ago
14

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

t to x from the second equation is substituted into the first equation.
2x – 3y = –29
x + 4y = 13

2(4y + 13) – 3y = –29

2(–4y + 13) – 3y = –29

2x – 3(4y + 13) = –29

2x – 3(–4y + 13) = –29 ...?
Mathematics
1 answer:
Alisiya [41]3 years ago
5 0
The answer is <span>2(–4y + 13) – 3y = –29

Step 1: Express </span><span>x from the second equation
Step 2: Substitute x into the first equation:

The system of equations is:
</span><span>2x – 3y = –29 
x + 4y = 13

Step 1: 
</span>The second equation is:    x + 4y = 13
Rearrange it to get x:         x = - 4y + 13

Step 2:
The first equation is:          2x – 3y = –29 
The second equation is:    x = - 4y + 13
Substitute x from the second equation into the first one:
2(-4y + 13) - 3y = -29

Therefore, the second choice is correct.
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We have that
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 </span>- 1/(2-c)=-1/-(c-2)=1/(c-2)

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(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)

(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2
(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4
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the solution is c=14
 
the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or 
<span>all real numbers except c=-2 and c=2</span>


5 0
3 years ago
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The mass of an ant is 1/10 of the load, which it can carry in one try. What is the mass of the ant, if in one time it can carry
Viefleur [7K]

If you call m the mass of the ant and l the load, we have the equation

m = \cfrac{l}{10}

In fact, the mass of the ant is one tenth of the load, which is exactly what this equation states.

Since we are given the load, we simply need to plug its value in the equation to deduce the mass of the ant:

m = \cfrac{\frac{7}{250}}{10} = \cfrac{7}{250}\cdot\cfrac{1}{10} = \cfrac{7}{2500}

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Answer:

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Step-by-step explanation:

Point slope form is

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Answer:

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Step-by-step explanation:

A ratio is a comparison of two quantities and can be written in several forms including fractions. It is most commonly written in fraction form or a:b.

To write a ratio, we count the number of each quantity we are comparing or use the variable for that quantity. We write radius:circumference. Recall, the circumference of a circle can be found using \pi d or 2\pi r.

We write r: \pi d  or r:2\pi r.

We can also write in fraction form:

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Answer:

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Step-by-step explanation:

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