<u> P = 2(L +W)</u>
Divide each side of the equation by 2 : P/2 = L + W
Subtract W from each side : <em> P/2 - W = L</em>
Answer:
it is moved 7 to the left of the parent function
Step-by-step explanation:
X - 10 >= -2
x will be greater than or equal to 8
First you want to know what y or x is i chose y for this on
so the equation i'm going to use is -2x-5y=3
i want to solve for y
-2x-5y=3
+2x +2x
-5y=2x+3
/-5 /-5 /-5
y=-2/5x+-3/5
Now that i solved for y we substitute our answer into the next equation to solve for x like this:
3x+8y=-6
3x+8(-2/5x+-3/5)=-6
3x+ -3.2x+-4.8=-6
-0.2x+-4.8=-6
+4.8 +4.8
-0.2x=-1.2
/-0.2 /-0.2
x=6
After you know what x is you substitute it in for any of the equations that we started with. I picked 3x+8y=-6 to find y.
3x+8y=-6
3*6+8y=-6
18+8y=-6
-18 -18
8y=-24
/8 /8
y=-3
Since we know what x and y are we substitute it with any of the equations that we started with. i picked -2x-5y=3
-2*6-5*-3=3
-12- -15=3
3=3
so our solution (6,-3) works
Answer:
8r^4
Step-by-step explanation:
√(64r^8) = √((8r^4)^2) = 8r^4
_____
You can make use of either or both of these rules of exponents:
(a^b)^c = a^(b·c) . . . . . used above
![\sqrt[n]{a}=a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Using the second rule, you can write the expression as ...
