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Alenkasestr [34]
3 years ago
9

Find the area of polygon PQRS.

Mathematics
1 answer:
Molodets [167]3 years ago
7 0

Answer:

12 unit squared....................

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<img src="https://tex.z-dn.net/?f=solve%20for%20%22m%22%20t%3D%5Cfrac%7Bms%7D%7Bm%2Bn%7D" id="TexFormula1" title="solve for &quo
dalvyx [7]

Answer:

\boxed{\sf \ \ \ m = -\dfrac{tn}{t-s} \ \ \ }

Step-by-step explanation:

Hello,

let s assume that m+n is different from 0

we have this equation and we need to find m as a function of t, s, and n

t=\dfrac{ms}{m+n}

<=>

(m+n)*t=ms\\\\ tm+tn=sm\\ (t-s)m = -tn\\ m = -\dfrac{tn}{t-s}

for t-s different from 0, so t different from s

hope this helps

4 0
3 years ago
pls asap its not 128......In how many ways can you put seven marbles in different colors into four jars? Note that the jars may
tangare [24]

Answer:

hope it helps

this is my best

please tell me if I'm wrong

4 0
3 years ago
7) Find the area of the shaded region:
aleksandr82 [10.1K]

Answer:

B

Step-by-step explanation:

The area of the biggest rectangle =

(9x - 2)(2x + 7) = 18 {x}^{2}  + 63x - 4x - 14  = 18 {x}^{2}   + 59x - 14

The area of the of the smallest rectangle inside=

3x(x + 12) = 3 {x }^{2}  + 36x

Then the area of the shaded region =

18 {x}^{2}  + 59x - 14 - (3 {x}^{2}   + 36x)    = 18 {x}^{2}  + 59x - 14 - 3 {x}^{2}  - 36x = 15 {x}^{2}  + 23x - 14

So, we choose B.

7 0
3 years ago
A solid lies between planes perpendicular to the​ x-axis at x = -2 and x = 2. The​ cross-sections perpendicular to the​ x-axis b
icang [17]

Answer:

V = 128π/3 vu

Step-by-step explanation:

we have that: f(x)₁ = √(4 - x²);  f(x)₂ = -√(4 - x²)

knowing that the volume of a solid is  V=πR²h, where R² (f(x)₁-f(x)₂) and h=dx, then

dV=π(√(4 - x²)+√(4 - x²))²dx;  =π(2√(4 - x²))²dx ⇒

dV= 4π(4-x²)dx , Integrating in both sides

∫dv=4π∫(4-x²)dx , we take ∫(4-x²)dx and we solve

4∫dx-∫x²dx = 4x-(x³/3) evaluated -2≤x≤2 or too 2 (0≤x≤2) , also

∫dv=8π∫(4-x²)dx evaluated 0≤x≤2

V=8π(4x-(x³/3)) = 8π(4.2-(2³/3)) = 8π(8-(8/3)) =(8π/3)(24-8) ⇒

V = 128π/3 vu

8 0
3 years ago
If a radioactive isotope has a half-life of 6 hours and 12 milligrams is initially present, how much will
Serhud [2]

Answer:0.75 milligrams will  be present in 24 hours

Step-by-step explanation:

Step 1

The formula for radioactive decay can be written as

N(t)=No (1/2)^(t/t 1/2)

where

No= The amount of the radioactive substance at time=0=milligrams

t 1/2= the half-life= 6 hours

t=24 hours

N(t) = the amount at time t

Step 2--- Solving

N(t)=No (1/2)^(t/t 1/2)

=N(t)=12 x ( 1/2) ^ (24/6)

= 12 x (1/2) ^4

= 12 x 0.0625

= 0.75 milligrams

3 0
3 years ago
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