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blsea [12.9K]
3 years ago
10

A direct variation function contains the points (2, 14) and (4, 28). Which equation represents the function?

Mathematics
2 answers:
IgorC [24]3 years ago
6 0
Direct variation mean x =ky so y = x/k

(2,14) mean y = kx so 14 = k*2 so 14 = 7*2 so 14 = 14 
(4,28) mean y = kx so 28 = k*4 so 28 = 7*4 so 28 = 28

from these result that the 3rd choice is right sure 


mash [69]3 years ago
6 0

y = 7x THIS IS THE ANSEWR

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<img src="https://tex.z-dn.net/?f=12x%20%5E%7B2%7D%20%20%2B%204x%20%2B%2020" id="TexFormula1" title="12x ^{2} + 4x + 20" alt="1
Nesterboy [21]
<h3>Answer: </h3>

The GCF is 4

The polynomial factors to 4(3x^2+x+5)

==========================================================

Further explanation:

Ignore the x terms

We're looking for the GCF of 12, 4 and 20

Factor each to their prime factorization. It might help to do a factor tree, but this is optional.

  • 12 = 2*2*3
  • 4 = 2*2
  • 20 = 2*2*5

Each factorization involves "2*2", which means 2*2 = 4 is the GCF here.

We can then factor like so

12x^2 + 4x + 20\\\\4*3x^2 + 4*x + 4*5\\\\4(3x^2 + x + 5)

The distributive property pulls out that common 4. We can verify this by distributing the 4 back in, so we get the original expression back again.

The polynomial inside the parenthesis cannot be factored further. Proof of this can be found by looking at the roots and noticing that they aren't rational numbers (use the quadratic formula).

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