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Reika [66]
3 years ago
11

To own and operate a home printer, it costs $100 for the printer and an additional $0.05 per page for ink. To print out pages at

an office store, it costs $0.25 per page. Let p represent number of pages.
(1) For the costs to be the same, how many pages do you need to print?
(2) How much does it cost to print that many pages?
Mathematics
2 answers:
Sergeu [11.5K]3 years ago
6 0

Answer: (1) You would need to print 500 pages

(2) To print 500 pages from home would cost $125

Step-by-step explanation: The cost of printing at home has been given as a fixed cost of 100 plus an additional variable cost of 0.05 per page for ink, that is, Cost = 100 + 0.05p. Also, to print at the office, the cost has been given as 0.25 per page, that is, Cost = 0.25p.

Therefore for the costs to be the same, we need to equate both cost functions (that is, C = C) as follows;

100 + 0.05p = 0.25p

Collect like terms and we now have,

100 = 0.25p - 0.05p

100 = 0.20p

Divide both sides of the equation by 0.2

500 = p

To print 500 pages at home therefore would cost,

C = 100 + 0.05p

C = 100 + 0.05(500)

C = 100 + 25

C = 125

Therefore to print 500 pages from home would cost $125

Softa [21]3 years ago
3 0

Answer:

1.) 500 pages

2.) $125

Step-by-step explanation:

Given that the printer cost $100. To operate at home will cost

100 + 0.05P

To print out pages at an office store, it will cost 0.25P

1.) For the costs to be the same, then

100 + 0.05P = 0.25P

0.25P - 0.05P = 100

0.20P = 100

P = 100/0.2

P = 500 pages

500 pages need to be printed

2.) How much does it cost to print that many pages?

Cost = 0.25P

= 0.25 × 500

= 125 dollars

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son4ous [18]

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Step-by-step explanation:

x - y = 2

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Select correct answer
Sergio [31]

Answer:

The values of p in the equation are 0 and 6

Step-by-step explanation:

First, you have to make the denominators the same. to do that, first factor 2p^2-7p-4 = \left(2p+1\right)\left(p-4\right)2p

2

−7p−4=(2p+1)(p−4)

So then the equation looks like:

\frac{p}{2p+1}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{5}{p-4}

2p+1

p

−

(2p+1)(p−4)

2p

2

+5

=−

p−4

5

To make the denominators equal, multiply 2p+1 with p-4 and p-4 with 2p+1:

\frac{p^2-4p}{(2p+1)(p-4)}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{10p+5}{(p-4)(2p+1)}

(2p+1)(p−4)

p

2

−4p

−

(2p+1)(p−4)

2p

2

+5

=−

(p−4)(2p+1)

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Since, this has an equal sign we 'get rid of' or 'forget' the denominator and only solve the numerator.

(p^2-4p)-(2p^2+5)=-(10p+5)(p

2

−4p)−(2p

2

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Now, solve like a normal equation. Solve (p^2-4p)-(2p^2+5)(p

2

−4p)−(2p

2

+5) first:

(p^2-4p)-(2p^2+5)=-p^2-4p-5(p

2

−4p)−(2p

2

+5)=−p

2

−4p−5

-p^2-4p-5=-10p+5−p

2

−4p−5=−10p+5

Combine like terms:

-p^2-4p+0=-10p−p

2

−4p+0=−10p

-p^2+6p=0−p

2

+6p=0

Factor:

p=0, p=6p

7 0
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Read 2 more answers
PLEASE HELP EASY MATH
prisoha [69]
Unit rates are easy you just take the first number and divide it by your second
15 divided by 5 is = 3
75 divided by 25 is = 3
80 divided by 4 is = 20
Please mark brainiest
Have a amazing day
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