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aniked [119]
3 years ago
9

The simulation kept track of the variables and automatically recorded data on object displacement, velocity, and momentum. If th

e trials were run on a real track with real gliders, using stopwatches and meter sticks for measurement, how might the data compare? Check all that apply.
- There would be variables that would be hard to control, leading to less reliable data.
- The data would be just as valid if it were recorded with a stopwatch.
- Meter sticks may lack precision or may be read incorrectly.
- Real glider data may vary since real collisions may involve loss of energy.
- Human error in recording or plotting the data could be a factor.
- Controlling real glider velocities by hand would be just as accurate as simulation controls.
Physics
2 answers:
wolverine [178]3 years ago
6 1

Answer:

1,3,5 are the actual correct answers, i just did the test

Explanation:

DiKsa [7]3 years ago
6 0
<h2><u>Answer:</u></h2>

The simulation kept track of the variables and automatically recorded data on object displacement, velocity, and momentum. If the trials were run on a real track with real gliders, using stopwatches and meter sticks for measurement, the data compared by the following statements:

1. (There would be variables that would be hard to control, leading to less reliable data.)

3. (Meter sticks may lack precision or may be read incorrectly.)

4. (Real glider data may vary since real collisions may involve loss of energy.)

5. (Human error in recording or plotting the data could be a factor.)


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A typical laboratory centrifuge rotates at 4000 rpm. Testtubes have to be placed into a centrifuge very carefully because ofthe
Bogdan [553]

Answer:

A)  a_c = 1.75 10⁴ m / s², B) a = 4.43 10³ m / s²

Explanation:

Part A) The relation of the test tube is centripetal

               a_c = v² / r

the angular and linear variables are related

              v = w r

we substitute

               a_c = w² r

let's reduce the magnitudes to the SI system

              w = 4000 rpm (2pi rad / 1 rev) (1 min / 60s) = 418.88 rad / s

               r = 1 cm (1 m / 100 cm) = 0.10 m

let's calculate

              a_c = 418.88² 0.1

               a_c = 1.75 10⁴ m / s²

part B) for this part let's use kinematics relations, let's start looking for the velocity just when we hit the floor

as part of rest the initial velocity is zero and on the floor the height is zero

                v² = v₀² - 2g (y- y₀)

                v² = 0 - 2 9.8 (0 + 1)

                v =√19.6

                v = -4.427 m / s

now let's look for the applied steel to stop the test tube

                v_f = v + a t

                0 = v + at

                a = -v / t

                a = 4.427 / 0.001

                a = 4.43 10³ m / s²

4 0
3 years ago
if the current in a wire is 2.0 amperes and the potential difference across the wire is 10 volts what is the resistance of the w
Pavlova-9 [17]

Answer:

R = 2Ω

Explanation:

Potential difference (V) = current (I) * Resistance (R)

V = IR

I = 2.0A

V = 10v

R = ?

V = IR

R = V / I

R = 10 / 2

R = 2Ω

The resistance across the wire is 2Ω

3 0
3 years ago
Read 2 more answers
If one gram of matter could be completely converted into energy, the yield would be
noname [10]

Answer:

Energy, E=9\times 10^{13}\ J

Explanation:

It is given that,

Mass of matter, m = 1 g = 0.001 Kg

If this matter is completely converted into energy, we need to find the yield. The mass of an object can be converted to energy as :

E=mc^2

c = speed of light

E=0.001\ kg\times (3\times 10^8\ m/s)^2

E=9\times 10^{13}\ J

So, the energy yield will be 9\times 10^{13}\ J. Hence, this is the required solution.

5 0
4 years ago
What is the Velocity of A on the graph?<br> Distance is in km and time is in Seconds?
sattari [20]

Answer:

15 km/s from the starting point

Explanation:

Velocity is total distace divided by total time.

From the picture, you can see that line consecutively traveled 30 kilometers- in 2 seconds.

(9 to 11 is two seconds, unless I'm wrong.)

So, total distance = 30 km. Total time = 2 seconds.

30/2 is 15.

the velocity of line A is 15 km/s from the starting point.

4 0
3 years ago
Read 2 more answers
if you dilute green tea 9.0, alkaline water 8.0, fruit juice 6.8, vinegar 3.5, and gatorade 3.0 which substance will have a high
tensa zangetsu [6.8K]

Answer:

green tea

Explanation:

According to the question

It is mentioned that

dilute green tea 9.0,

alkaline water 8.0,

fruit juice 6.8,

vinegar 3.5,

and Gatorade 3.0

Now based on the above information

As it can bee seen that the Dilute green tea contains higher pH as compared with the others

So, the substance that have a bigger or higher pH is green tea

8 0
3 years ago
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