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3 years ago

Which of the following bonds strength ranks in the correct order?

Physics

2 answers:

Arturiano [62]3 years ago

7 0

Answer:

This answer to the problem is D

TEA [102]3 years ago

4 0

Answer:

the answer is A

Explanation:

The answer is A

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What force causes objects to stay in orbit?

-BARSIC- [3]

Answer:

gravitational force

Explanation:

The reason that an object will maintain its orbit, regardless of its position in the orbit, is because the gravitational force from the larger object will constantly act upon the smaller object, thereby pulling the smaller object towards the larger object

7 0

3 years ago

Read 2 more answers

A worker exerts a pulling force on a box. The worker exerts this force by attaching a rope to the box and pulling on the rope so

shusha [124]

Answer:

The magnitude of the pulling force is 20.66% of the gravitational force acting on the box

Explanation:

Accelerated Motion

The net force exerted on a body is the (vector) sum of all forces applied to the body. The net force can be decomposed in its rectangular components and the dynamics of the body can be studied in each direction x,y separately.

Let's start off by calculating the acceleration the worker gives to the box when pulling it. The distance traveled by the box initially at rest in a time t at an acceleration a is given by

$\displaystyle x=\frac{at^2}{2}$

Solving for a

$\displaystyle a=\frac{2x}{t^2}$

$\displaystyle a=\frac{2\cdot 10}{5.12^2}$

$a=0.763\ m/s^2$

Now we analyze the geometric of the forces applied to the box. Please refer to the free body diagram provided below.

The forces in the y-axis must be in equilibrium since no movement takes place there, thus, being g the acceleration of gravity:

$T_y+N=m.g$

There Ty is the vertical component of the tension of the rope, N is the normal force, and m is the mass of the box

The decomposition of T gives us

$T_y=Tsin\theta$

$T_x=Tcos\theta$

Solving the above equation for N

$Tsin\theta+N=m.g$

$N=m.g-Tsin\theta\text{..........[1]}$

Now for the x-axis, there are two forces acting on the box, the x-component of the tension and the friction force Fr. Those forces are not equilibrated, thus acceleration is produced:

$Tcos\theta-F_r=m.a$