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4 years ago

What is the purpose of the key or legend on a map

1 answer:

8 0

<span>Map Key or Legend. A map key or legend is included with a map to unlock it. It gives you the information needed for the map to make sense. Maps often use symbols or colors to represent things, and the map key explains what they mean</span>

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Modern commercial airliners are largely made of aluminum, a light and strong metal. But the fact that aluminum is cheap enough t

iVinArrow [24]

Answer:

n = 291 people

Explanation:

To solve this interesting problem we are going to take some data from the tables, the density of 7075 aluminum is 2.8 103 kg / m³, the density of 316 stainless steel is 7980 kg / m³, where we have selected one of the most used alloys in for its resistance.

The average mass of a passenger is mo = 80kg and the Boeing 747 aircraft can carry 550 passengers and a crew of 18 people with a length of 70.66 m,

Let's start by calculating the mass of the empty plane and the mass of the passengers

ρ_Al = m_Al / V

m_Al = ρ_Al V

m_passenger= #_pasajeros 80

m_passenger = 550 m₀

The total mass of the plane is

M = m_passengers + m_Al

If the plane is built face to face, the mass of this material is

ρ_Acero = m_steel / V

the total mass of avino is

M = m_pasajeros` + m_steel

As they indicate the total mass of the plane must remain constant

m_passengers + m_Al = m_passengers` + m_steel

let's substitute the values

550 m₀ + 2.8 103 V = n m₀ + 7.98 103 V

where V is the volume of the material used which is the same in both cases

n = 550 mo + (2.8 - 7.98) 103 V = n mo

n = n = 550 + (2.8 - 7.98) 103 V / mo

The calculation of the volume of material used depends on the thickness of the sheet and the resistance of the material, if it assumes that it has the same thickness, e = 1 cm, approximate the volume to the length of the circle by the length of the cylinder by the thickness

V = (2π r) L e

the diameter of the plane approximately the height of the person

d = 1.8 m

V = 2π (1.8 / 2) 70.66 1 10⁻²

V = 3.9957 m³

we substitute

n = 550 - 5.18 10³ (3.9957) / 80

n = 550 - 258.7

n = 291 people

3 0

3 years ago

The current through a 0.2-H inductor is i(t) = 10te–5t A. What is the energy stored in the inductor?

lakkis [162]

Answer:

E = 10t^2e^-10t Joules

Explanation:

Given that the current through a 0.2-H inductor is i(t) = 10te–5t A.

The energy E stored in the inductor can be expressed as

E = 1/2Ll^2

Substitutes the inductor L and the current I into the formula

E = 1/2 × 0.2 × ( 10te^-5t )^2

E = 0.1 × 100t^2e^-10t

E = 10t^2e^-10t Joules

Therefore, the energy stored in the inductor is 10t^2e^-10t Joules

6 0

3 years ago

PLEASE HELP!!!

Harman [31]

The wind direction changed from morning to night because land and water absorbing solar energy unequally.

<h3>Convection current</h3>

Convection is said to occur when there is heat transfer by an actual movement of participles from place to place. The movement of air mass (wind) is affected by the relative amounts of solar energy absorbed by the land and sea.

Hence, the wind direction changed from morning to night because land and water absorbing solar energy unequally.

Learn more about convection current: brainly.com/question/12841408

3 0

3 years ago

A charge Q acts on a point charge to create an electric field. Its strength, measured a distance of 40 cm away is 100 N/C. What

KIM [24]

Answer:

$E_2=80N/C$

Explanation:

From the question we are told that:

Initial Distance $d_1=40cm=>0.4m$

Initial Electric field strength $E_1=100N/C$

Final Distance $d_2=20cm=>0.20m$

Generally the equation for Electric field is mathematically given by.

$E=\frac{kq}{d^2}$

$q=\frac{100*(0.4)^2}{K}$

Substituting q for $d=20cm$

$E_2=\frac{k}{0.2}*\frac{100*(0.4)^2}{K}$

$E_2=80N/C$

6 0

3 years ago

You are on the roof of the physics building, 46.0 above the ground . Your physics professor, who is 1.80 tall, is walking alongs

nekit [7.7K]

There is one mistake in the question as unit of height of building is not given.So I assume it as meter.The complete question is here

You are on the roof of the physics building, 46.0 m above the ground. Your physics professor, who is 1.80 m tall, is walking alongside the building at a constant speed of 1.20 m/s. If you wish to drop an egg on your professor’s head, where should the professor be when you release the egg? Assume that the egg is in free fall.

Answer:

d=3.67 m

Explanation:

Height of building=46.0 m

First we need to find time taken by egg to reach 1.80 m above the surface

So to find time use below equation

$S=vt+\frac{1}{2} gt^{2}\\ (46.0-1.80)m=(om/s)t+\frac{1}{2}(9.8m/s^{2} )t^{2}\\t=\sqrt{\frac{(46.0-1.80)m}{4.9} }\\ t=3.06s$

As velocity 1.20m/s is given and we have find time.So we can easily find the distance

$distance=velocity*time\\d=v*t\\d=(1.20m/s)*(3.06s)\\d=3.67m$

3 0

3 years ago