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masya89 [10]
3 years ago
7

if the current in a wire is 2.0 amperes and the potential difference across the wire is 10 volts what is the resistance of the w

ire to the nearest tenth of an ohm ?
Physics
2 answers:
svp [43]3 years ago
4 0

Answer:Its 5 ohms

Explanation:trust me lol

Pavlova-9 [17]3 years ago
3 0

Answer:

R = 2Ω

Explanation:

Potential difference (V) = current (I) * Resistance (R)

V = IR

I = 2.0A

V = 10v

R = ?

V = IR

R = V / I

R = 10 / 2

R = 2Ω

The resistance across the wire is 2Ω

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By equation of equilibrium and friction:

Fb = Kx = 15(0.175) = 2.625 kN.

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Fa = usNa = 0.35Na

Fb = 0.35Nb

Nb = 2.625 = 0; Nb = 2.625 kN

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P – (0.35 * 2.625) – 0.35 (2.841) cos 10 – 2.841 sin 10 = 0

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7 0
4 years ago
2. A phone is being charged using a current of 0.444 A.
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2. A phone is being charged using a current of 0.444 A.
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3 years ago
The kinetic energy of an object with a mass of 6.8 kg and a velocity of 5.0 m/s is [BLANK] J. (Report the answer to two signific
dmitriy555 [2]
<h2>Hello!</h2>

The answer is:

The kinetic energy of the object is equal to 85 J.

<h2>Why?</h2>

The kinetic energy involves the speed and the mass of an object in motion. We can calculate the following the work needed to speed an object (kinetic energy) using the equation:

KineticEnergy=\frac{1}{2}mv^{2}

Where,

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v, is the speed of the object.

Now, we are given:

mass=m=6.8kg\\speed=v=5\frac{m}{s}

So, substituting and calculating the kinetic energy of the object, we have:

KineticEnergy=\frac{1}{2}*6.8kg*(5\frac{m}{s})^{2}

KineticEnergy=\frac{1}{2}*6.8kg*(25\frac{m^{2}}{s^{2}})

KineticEnergy=\frac{1}{2}*170kg\frac{m^{2}}{s^{2}}

KineticEnergy=85kg\frac{m^{2}}{s^{2}}=85J

We have that the kinetic energy of the object is equal to 85 J.

Have a nice day!

8 0
3 years ago
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The principle of conservation of momentum is most similar to which of newton's laws of motion?
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Newton’s Thrid Law, which states that for every reaction there is an opposite reaction.
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3 years ago
Two particles, each with charge Q, and a third charge q, are placed at the vertices of an equilateral triangle as shown. The tot
Gelneren [198K]

Answer:

<em>D. The total force on the particle with charge q is perpendicular to the bottom of the triangle.</em>

Explanation:

The image is shown below.

The force on the particle with charge q due to each charge Q = \frac{kQq}{r^{2} }

we designate this force as N

Since the charges form an equilateral triangle, then, the forces due to each particle with charge Q on the particle with charge q act at an angle of 60° below the horizontal x-axis.

Resolving the forces on the particle, we have

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The above indicates that there is no resultant force in the x-axis, since it is equal to zero (N_{x} = 0).

The total force is seen to act only in the y-axis, since it only has a y-component equivalent to 1.732 times the force due to each of the Q particles on q.

<em>The total force on the particle with charge q is therefore perpendicular to the bottom of the triangle.</em>

5 0
4 years ago
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