By equation of equilibrium and friction:
Fb = Kx = 15(0.175) = 2.625 kN.
The wedge is on the verge of moving right then slipping will
have to occur at both contact surfaces.
Fa = usNa = 0.35Na
Fb = 0.35Nb
Nb = 2.625 = 0; Nb = 2.625 kN
Nacos10 – 0.35Na sin 10 = 2.625 = 0
Na = 2.841 kN
P – (0.35 * 2.625) – 0.35 (2.841) cos 10 – 2.841 sin 10 = 0
P = 2.39 kN
2. A phone is being charged using a current of 0.444 A.
If the resistance of the phone is 10 , what is the
voltage being applied to the phone?
<h2>
Hello!</h2>
The answer is:
The kinetic energy of the object is equal to 85 J.
<h2>
Why?</h2>
The kinetic energy involves the speed and the mass of an object in motion. We can calculate the following the work needed to speed an object (kinetic energy) using the equation:

Where,
m, is the mas of the object
v, is the speed of the object.
Now, we are given:

So, substituting and calculating the kinetic energy of the object, we have:




We have that the kinetic energy of the object is equal to 85 J.
Have a nice day!
Newton’s Thrid Law, which states that for every reaction there is an opposite reaction.
Answer:
<em>D. The total force on the particle with charge q is perpendicular to the bottom of the triangle.</em>
Explanation:
The image is shown below.
The force on the particle with charge q due to each charge Q = 
we designate this force as N
Since the charges form an equilateral triangle, then, the forces due to each particle with charge Q on the particle with charge q act at an angle of 60° below the horizontal x-axis.
Resolving the forces on the particle, we have
for the x-component
= N cosine 60° + (-N cosine 60°) = 0
for the y-component
= -f sine 60° + (-f sine 60) = -2N sine 60° = -2N(0.866) = -1.732N
The above indicates that there is no resultant force in the x-axis, since it is equal to zero (
= 0).
The total force is seen to act only in the y-axis, since it only has a y-component equivalent to 1.732 times the force due to each of the Q particles on q.
<em>The total force on the particle with charge q is therefore perpendicular to the bottom of the triangle.</em>