Question

if the temperature remains constant and the initial pressure is 101.3 kPa then what is the new pressure reading when the volume is doubled

Answer 1

Answer:

             The pressure will decrease by half.

Explanation:

Data Given:

                  P₁  =  101.3 kPa  

                  V₁  =  X

                  V₂  =  2X

                   P₂  =  ??

Let us suppose the initial volume is 5 L and the final volume when doubled is 10 L. Then According to Boyle's Law, " The Volume of a given mass of gas at constant temperature is inversely proportional to the applied Pressure". Mathematically the initial and final states of gas are given as,

                                     P₁ V₁  =  P₂ V₂    ----------- (1)

Solving equation 1 for P₂,

                                     P₂  =  P₁ V₁ ÷ V₂

Putting values,

                                     P₂  =  (101.3 kPa × 5 L) ÷ 10 L

                                     P₂  =  50.65 kPa

Result:

          As the volume is doubled, the pressure is decreased from 101.3 kPa to 50.65 kPa or it has decreased by half.