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vagabundo [1.1K]
2 years ago
5

What is the empirical formula and empirical formula mass for the following compound? C3H6O3?

Chemistry
1 answer:
babunello [35]2 years ago
5 0
Answer: C3H6O3 > CH2O
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As a form of energy, light has specific properties such as color and brightness. Some properties can only be seen with special t
Sergeu [11.5K]

Answer:

D. As white light passes through a prism , it bends and separates into different colors

Explanation:

When light enters a prism, it experiences a phenomenon called 'refraction'.

Refraction occurs when light crosses the interface between two mediums with different optical density; when this happens, the light bends and also changes speed.

The angle at which the ray of light is refracted into the second medium depends on the optical density of the two mediums, but also on the wavelength of the light.

In particular, longer wavelengths (red color) are refracted the least, while shorter wavelengths (violet color) are refracted the most.

As a result, when white light (consisting of all the colors of visible light) enters into a prism, they different wavelengths are separated: therefore, white light separates into different colors.

So, the correct answer is

D. As white light passes through a prism , it bends and separates into different colors

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3 years ago
Write your name on a piece of paper with a water soluble marker and place the slime on top of it and remove very quickly before
creativ13 [48]
Uh i did this because it made me curious... i may have done it wrong nothing happened
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3 years ago
A student placed 18.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
mamaluj [8]

Answer:

1.30464 grams of glucose was present in 100.0 mL of final solution.

Explanation:

Molarity=\frac{moles}{\text{Volume of solution(L)}}

Moles of glucose = \frac{18.5 g}{180 g/mol}=0.1028 mol

Volume of the solution = 100 mL = 0.1 L (1 mL = 0.001 L)

Molarity of the solution = \frac{0.1028 mol}{0.1 L}=1.028 mol/L

A 30.0 mL sample of above glucose solution was diluted to 0.500 L:

Molarity of the solution before dilution = M_1=1.208 mol

Volume of the solution taken = V_1=30.0 mL

Molarity of the solution after dilution = M_2

Volume of the solution after dilution= V_2=0.500L = 500 mL

M_1V_1=M_2V_2

M_2=\frac{M_1V_1}{V_2}=\frac{1.208 mol/L\times 30.0 mL}{500 mL}

M_2=0.07248 mol/L

Mass glucose are in 100.0 mL of the 0.07248 mol/L glucose solution:

Volume of solution = 100.0 mL = 0.1 L

0.07248 mol/L=\frac{\text{moles of glucose}}{0.1 L}

Moles of glucose = 0.07248 mol/L\times 0.1 L=0.007248 mol

Mass of 0.007248 moles of glucose :

0.007248 mol × 180 g/mol = 1.30464 grams

1.30464 grams of glucose was present in 100.0 mL of final solution.

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Smog

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How many kilojoules are released when 2.25 mol of H2O2 reacts?
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Answer:

230.3 kJ

Some chemical reactions show release of heat while some show absorption of heat. On these bases, the reaction is classified as either endothermic or exothermic. Negative sign of ΔH means exothermic reaction.

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