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Ivahew [28]
2 years ago
14

What happens to electrons in an ionic bond?

Chemistry
1 answer:
ElenaW [278]2 years ago
4 0

Answer:

the metal loses electrons to become a positively charged cation

Explanation:

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6.75 L of carbon dioxide gas are stored at a pressure of 175 atm. If the temperature and number of gas particles do not change,
I am Lyosha [343]

Answer:

4.24 L

Explanation:

  • 6.75 L - 175 atm

x. - 110 atm

  • <u>175atm </u><u>x</u>=<u>742.5L /atm</u>

175atm 175atm

  • therefore x=4.24 L
3 0
3 years ago
What is the formal charge of nitrogen in no2cl
Gre4nikov [31]

Answer:

The formal charge on nitrogen in NO_{2}Cl is +1.

Explanation:

The structure of NO_{2}Cl is as follows.

(In attachment)

Formal\, charge = Valence\, electron - (nonbonding\, electrons + \frac{Bonding\,electrons}{2})

From the structure, Nitrogen has no non bonding electrons. Nitrogen has four bonds and each bond corresponds to 2 electrons. Hence, nitrogen have eight bonding electrons and five valence electrons.

Formal\,charge\,on\,nitrogen = 5-[0+ \frac{8}{2}]= +1

Therefore, The formal charge on nitrogen in NO_{2}Cl is +1.

6 0
3 years ago
For which of the following processes would you expect there to be an increase in entropy? Ag+(aq) + Cl-(aq) AgCl(s) H2O(g) H2O(l
Lyrx [107]
CaBr₂(s) → Ca⁺²(aq) + 2Br⁻ (aq)     ΔS>0
6 0
2 years ago
Read 2 more answers
Which of the following is true for a chemical reaction at equilibrium?
victus00 [196]

Answer:

youre gonna have to include the answers for me to help

Explanation:

7 0
2 years ago
Consider the reaction 2 al + Fe2O3 to 2Fe + Al2O3. If 60.0g of Al is reacted with excess Fe2O3, determine the amount (in moles)
olganol [36]

 The  amount  of  Al2O3  in moles=  1.11 moles    while in  grams   = 113.22 grams


    <em><u>calculation</u></em>

     2 Al  + Fe2O3 → 2Fe  + Al2O3

    step  1: find the moles of Al  by  use of <u><em>moles= mass/molar  mass  </em></u>formula

    =  60.0/27= 2.22  moles


    Step 2: use the mole ratio to determine the  moles of Al2O3.

 The  mole ratio  of Al : Al2O3 is  2: 1 therefore the moles of Al2O3= 2.22/2=1.11  moles


Step 3:    finds the mass  of  Al2O3  by us of  <u><em>mass= moles x molar mass</em></u><em> </em>formula.

The molar  mass of Al2O3  =  (2x27)  +( 16 x3) = 102  g/mol

mass is therefore=  102  g/mol  x 1.11= 113.22 grams


             

7 0
2 years ago
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