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makvit [3.9K]
2 years ago
13

What laws do astronomers use to indirectly learn about stars?​

Chemistry
1 answer:
Maru [420]2 years ago
6 0

Answer

<em>Laws </em><em>that </em><em>are </em><em>used </em><em>by </em><em>astronomers </em><em>to </em><em>learn </em><em>about </em><em>stars </em><em>indirectly </em><em>are </em><em>as </em><em>given </em><em>below:</em><em>-</em>

  • <em>Kirchhoff's First La</em><em>w</em>
  • <em>Cassini's laws</em>

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How is a metallic compound different from an ionic compound?
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Iron (Fe) is classified as a metal while Silicon (Si) is classified as a metalloid. Which physical property do these two element
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VikaD [51]

Answer : The value of \Delta G^o and K is, -180 kJ/mol and 3.6\times 10^{31}

Explanation :

The balanced cell reaction will be,

Pb(s)+2Ag^+(aq)\rightarrow Pb^{2+}(aq)+2Ag(g)

The half-cell reactions are:

Oxidation reaction (anode) : Pb(s)\rightarrow Pb^{2+}(aq)+2e^-

Reduction reaction (cathode) : 2Ag^+(aq)+2e^-\rightarrow 2Ag(g)

Relationship between standard Gibbs free energy and standard electrode potential follows:

\Delta G^o=-nFE^o_{cell}

where,

\Delta G^o = standard Gibbs free energy

F = Faraday constant = 96500 C

n = number of electrons in oxidation-reduction reaction = 2

E^o_{cell} = standard electrode potential of the cell = 0.93 V

Now put all the given values in the above formula, we get:

\Delta G^o=-2\times 96500\times 0.93

\Delta G^o=-179490J/mol=-179.49kJ/mol\approx -180kJ/mol

Now we have to calculate the value of 'K'.

\Delta G^o=-RT\ln K

where,

\Delta G_^o =  standard Gibbs free energy  = -180 kJ/mol

R = gas constant = 8.314\times 10^{-3}kJ/mole.K

T = temperature = 298 K

K = equilibrium constant = ?

Now put all the given values in the above formula 1, we get:

-180kJ/mol=-(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln K

K=3.6\times 10^{31}

Therefore, the value of \Delta G^o and K is, -180 kJ/mol and 3.6\times 10^{31}

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3 years ago
The atomic mass of seven atoms of antimony is ?
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Answer:

Percent composition by element

Element Symbol Atomic Mass

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Explanation:

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