Odd functions go up and down in the ends
even function either go up on both ends or down on both end ,
so i think the answer would be :
since n is odd and a is positive , the end behavior is up and down
hope this helps
Answer:
You had $30
Step-by-step explanation:
The answer is 30 because he said that he had 10 dollars and 20 which means he had 30 dollars the other money was given to him.
P.S Can I have brainliest? (I don't deserve brainliest the other guy got it first.)
The slope is 0.5 tablespoon per minute, which you can deduct from the increase of y from one minute to the next.
The initial value (at x=0) is 1. So the equation is:
y = 0.5x + 1. That's the last one in the list, answer D.
Answer:
4
Step-by-step explanation:
When you are looking at a graph, a minimum point would be where the curve is decreasing, then begins to increase. Right at the point where it switches, the slope is a horizontal line, or 0. We can take the derivative is f(x), then look for all the x values where the slope (which is equal to the first derivative) is equal to zero.
f'(x) = 2 * -4sin(2x - pi)
The 2 comes from the derivative of the inside, 2x-pi.
So now set the derivative equal to 0.
-8sin(2x-pi) = 0
We can drop the -8 by dividing both sides by -8.
sin(2x-pi) = 0
This can be rewritten as arcsin(0) = 2x-pi
So when theta equals 0, what is the value of sin(theta)? At an angle of 0, there is just a horizontal line pointing to the right on the unit circle with length of 1. Sine is y/h, but there is no y value so it is just 0. If arcsin(0) = 0, we can now set 2x-pi = 0
2x = pi
x = pi/2
This is a critical number. To find the minimum value between 0 and pi, we need to find the y values for the endpoints and the critical number.
f(0) = -4
f(pi/2) = 4
f(pi) = -4
So the minimum points are at x=0 and x=pi
