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3 years ago

4 is 20% of what number

Mathematics

2 answers:

ladessa [460]3 years ago

8 0

I think the answer would be 20..

KiRa [710]3 years ago

7 0

4 is 20% of 20. Hope this helps!

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The LCD for 1 over 7 and 1 over 8 is

asambeis [7]

The least common denominator would be 56. Hope I helped you!

7 0

2 years ago

Given: ABCD is a ∥-gram, BF ⊥ CD , BE ⊥ AD, Prove: △ABE∼△CBF

drek231 [11]

Answer:

Hence proved △ABE∼△CBF.

Step-by-step explanation:

Given,

ABCD is a parallelogram.

BF ⊥ CD and

BE ⊥ AD

To Prove : △ABE∼△CBF

We have drawn the diagram for your reference.

Proof:

Since ABCD is a parallelogram,

So according to the property of parallelogram opposite angles are equal in measure.

$\therefore m\angle A = m\angle B$ ⇒1

And given that BF ⊥ CD and BE ⊥ AD.

So we can say that;

$m\angle F=m\angle E=90\°$ ⇒2

Now In △ABE and △CBF

∠A = ∠C (from 1)

∠E = ∠F (from 2)

So by A.A. similarity postulate;

△ABE∼△CBF

7 0

3 years ago

I need help plsss I will give u more points

lions [1.4K]

Answer:

The value of 0.9* 10² is D.90.
4*(12-8)+2³

4*4+2³
16+8
24

False : it is to add 16+8

b.

False : its 8.

c.

True.

d.

False : its 24.

3.

side  of cube [a]=2ft

volume of cube [V]=a³=2³=8ft³

He needs 1 bag to buy.As its volume is equal.

7 0

2 years ago

Help me please (20 points) (2 questions) PLEASE (picture below)

Wittaler [7]

The first question is 2, 12, and 14 but i’m sorry i don’t know the second :(

7 0

3 years ago

A drawer contains 3 white shirts, 2 blue shirts, and 5 gray shirts. A shirt is randomly

shutvik [7]

Answer:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

Step-by-step explanation:

Given that

3 white, 2 blue and 5 gray shirts are there.

To find:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = ?

Solution:

Here, total number of shirts = 3+2+5 = 10

First of all, let us learn about the formula of an event E:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(First\ White) = \dfrac{\text{Number of white shirts}}{\text {Total number of shirts left}}$

$P(First\ White) = \dfrac{3}{10}$

Now, this shirt is set aside.

So, total number of shirts left are 9 now.

$P(First\ White\ and\ second\ gray) = P(First White) \times P(Second\ Gray)\\\Rightarrow P(First\ White\ and\ second\ gray) = P(First White) \times \dfrac{\text{Number of gray shirts}}{\text{Total number of shirts left}}\\\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{3}{10} \times \dfrac{5}{9}\\\Rightarrow P(First\ White\ and\ second\ gray) = \dfrac{1}{2} \times \dfrac{1}{2}\\\Rightarrow P(First\ White\ and\ second\ gray) = \bold{\dfrac{1}{4} }$

So, the answer is:

Probability that first shirt is white and second shirt is gray if first shirt selected is set aside = $\frac{1}{4}$

4 0

3 years ago