This would be the Transitive Property of Congruence.

This property of congruence states that if two angles/segments/polygons are both congruent to something else, then they are congruent to each other.

Hope this helps! :)

5 0

3 years ago

The value of x must be greater than 0 1 3 7

Gre4nikov [31]

Answer:

The value of x should be greater than 3.

Step-by-step explanation:

Given that,

The AB is 12 units.

The AC is 15 units.

We need to find the value of BC.

Based on the above information, the calculation is as follows:

As we know that

The sum of two sides length is always more than the 3rd one.

Based on this,

12 + 15 > x

x < 27

15 + x >12

x >-3

12 + x > 15

x >3

5 0

2 years ago

Which expression is the completely factored form of x^6– 64y^3?

PSYCHO15rus [73]

Answer:

$(x^2-4y)(x^4+4x^2y+16y^2)$

Step-by-step explanation:

Factoring

We need to recall the following polynomial identity:

$(a^3-b^3)(a-b)(a^2+ab+b^2)$

The given expression is:

$x^6- 64y^3$

To factor the above expression, we need to find a and b, knowing a^3 and b^3. a is the cubic root of a^3, and b is the cubic root of b^3:

$a=\sqrt[3]{x^6}=x^2$

$b=\sqrt[3]{64y^3}=4y$

Now we apply the identity:

$x^6– 64y^3=(x^2-4y)[(x^2)^2+(x^2)*(4y)+(4y)^2]$

Operating:

$x^6– 64y^3=(x^2-4y)[x^4+4x^2y+16y^2]$

The remaining factors cannot be factored in anymore. Thus the completely factored form is:

$\boxed{(x^2-4y)(x^4+4x^2y+16y^2)}$

5 0

3 years ago