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3 years ago

9

Find the sum. (5-21) + (-7+81)

2 answers:

sergij07 [2.7K]3 years ago

6 0

58

First solve what is inside the parentheses (PEMDAS)

(5-21)+(-7+81)
(-16)+(74)
Add
58

Hope this helps! :)

Rom4ik [11]3 years ago

4 0

Answer:

58

Step-by-step explanation:

(5-21) is -16 and (-7+81) is 74,so 74+-16 is 58

Mark me brainliest if this helped:D

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Graph the function y=-|x|+9

MakcuM [25]

Answer:

Graph is attached :)

Step-by-step explanation:

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2 years ago

Solve the following system of equations by using the substitution method.

Hatshy [7]

X = y + 3
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Solution..
---------------

Substitute for x=y+3 in the second equation...

2x+y = 9

2(y+3)+y=9

2y+6+y=9
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3y=3
y=3/3
y=1....

Substitute for y=1 in the first equation...

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x = 1+3
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Am sure the answer is quite evident now...

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Four sizes of scaled text are shown. What is the unknown scale size?

Nesterboy [21]

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3 years ago

Read 2 more answers

Can SOMEBODYYY please do the maths!!! PLeassssssssssssseeeeeeee

Anna11 [10]

Answer:

<h2>see below</h2>

Step-by-step explanation:

<h3>Question-6:</h3>

we are given a equation

$\sf \displaystyle \: \log_{4}( - x) + \log_{4}( 6 - x) = 2$

to solve so

recall logarithm multiplication law:

$\sf \displaystyle \: \log_{4}( - x \times (6 - x)) = 2$

simplify multiplication:

$\sf \displaystyle \: \log_{4}( - 6 x + {x}^{2} ) = 2$

remember $\displaystyle \log_{4}(4^2)=2$

so

$\sf \displaystyle \: \log_{4}( - 6 x + {x}^{2} ) = \log_{4}( {4}^{2} )$

cancel out $\log_4$ from both sides:

$\sf \displaystyle \: - 6 x + {x}^{2} = {4}^{2}$

simplify squares:

$\sf \displaystyle \: - 6 x + {x}^{2} = 16$

move left hand side expression to right hand side and change its sign:

since we are moving left hand side expression to right hand side there'll be only 0 left in the left hand side

$\sf \displaystyle \: - 6 x + {x}^{2} - 16 = 0$

rewrite it to standard form i.e ax²+bx+c=0

$\sf \displaystyle \: {x}^{2} - 6x - 16 = 0$

rewrite -6x as 2x-8x:

$\sf \displaystyle \: {x}^{2} + 2x - 8x - 16 = 0$

factor out x and 8:

$\sf \displaystyle \: x {(x}^{} + 2) - 8(x + 2) = 0$

group:

$\sf \displaystyle \: (x - 8){(x}^{} + 2) = 0$

$\displaystyle \: x = 8 \\ x = - 2$

$\therefore \: x = - 2$

<h3>Question-7:</h3>

move left hand side log to right hand side:

$\displaystyle \: \log(x ) + \log(x - 21) = 2$

use mutilation logarithm rule;

$\displaystyle \: \log( {x}^{2} - 21x) = 2$

$\log(10^2)=2$ so

$\displaystyle \: \log( {x}^{2} - 21x) = \log({10}^{2} )$

cancel out log from both sides:

$\displaystyle \: {x}^{2} - 21x = 100$

make it standard form:

$\displaystyle \: {x}^{2} - 21x - 100= 0$

factor:

$\displaystyle \: {(x} + 4)(x - 25)= 0$

so

$\displaystyle \: x = 25$

5 0

2 years ago

Drew orders a video game online for $50.00. He has a 30% discount

Damm [24]

50(30%) = 15

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35 (6%) = 2.1

35 + 2.1 = $37.10

the total cost of his order is $37.10 !!

4 0

3 years ago