Question

Please help urgent easy question,just no 8

Answer 1

Answer:

Tanya is 14; Ruby is 11.

Step-by-step explanation:

Let T represent Tanya's current age and let R represent Ruby's current age.

We know that their ages add up to 25. So:

$T+R=25$

8 years ago, Tanya was twice as old as Ruby. In other words, Tanya's current age minus 8 is the same as Ruby's current age minus 8 times 2. So:  

$T-8=2(R-8)$

We have a system of equations. We can solve by substitution. From the first equation, subtract R from both sides:

$T=25-R$

Substitute this into the second equation:

$(25-R)-8=2(R-8)$

On the left, subtract. On the right, distribute:

$17-R=2R-16$

Add 16 to both sides. The right side cancels:

$33-R=2R$

Add R to both sides. The left cancels:

$33=3R$

Divide both sides by 3:

$R=11$

So, Ruby is currently 11 years old.

So, Tanya is currently 25-11 or 14 years old.

Check:

8 years ago, Ruby was 11-8 or 3 years old.

8 years ago, Tanya is 14-8 or 6 years old.

Tanya's age of 6 is 2 times Ruby's age of 3 so our answer is correct.

Answer 2

Answer:

Ruby is 11. Tanya is 14.

Step-by-step explanation:

Let Ruby's age eight years ago be x.

Tanya's age eight years ago = 2x.

Ruby's age now = x + 8

Tanya's age now = 2x + 8

Total age = $x+8+2x+8=25$

$3x+16=25$

Subtract 16 from both sides:

$3x+16-16=25-16$

$3x=9$

Divide both sides by 3:

$\frac{3x}{3} =\frac{9}{3}$

$x=3$

Ruby's age now $=x+8=3+8=11$

Tanya's age now $=2x+8=2(3)+8=6+8=14$