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3 years ago

Which is the image of ABC for a 90° counterclockwise rotation about P?

Mathematics

2 answers:

timofeeve [1]3 years ago

6 0

The answer is EFD because the turn is counterclockwise, around point P

- Your welcome

balu736 [363]3 years ago

5 0

Answer:

The triangle DEF

Step-by-step explanation:

If we see triangle ABC then by observing then we can say BC is base, AC is perpendicular and AB is hypotenuse .

When we rotate triangle ABC counter-clock wise rotation about P then

Then base BC becomes perpendicular of triangle, AC becomes base of triangle and hypotenuse AB remains same .

We can see this process through diagram.

Hence, the final triangle we obtain after 90° rotation is look similar as triangle DEF

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Find the equation of this line in slope intercept form y-2=1/2(x+8)

Andrews [41]

Answer
Root-(-12,0)
Vertical intercept- (0,6)

7 0

3 years ago

Use the compound interest formula to determine the final value of the following amount. $1900 at 10.4% compounded monthly for 4.

nikklg [1K]

Answer:

$3027.80

Explanation:

The compound interest formula is the following.

$A=P(1+\frac{r}{n})^{nt}$

where

A = final amount

P = principle amount

r = interest rate / 100

n = number of compounds per interval

t = time interval

Now in our case,

A = unknown

P = $1900

r = 10.4/100

n = 12 months / year ( because the interest is compounded monthly)

t = 4.5 yrs

Therefore, the compound interest formula gives

$A=1900(1+\frac{10.4/100}{12})^{12*4.5}$

Using a calculator, we evaluate the above to get

$\boxed{A=\$3027.80}$

which is our answer!

8 0

1 year ago

A computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

taurus [48]

Answer:

(a) 0.8836

(b) 0.6096

(c) 0.3904

Step-by-step explanation:

We are given that a computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

(a) Two computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 2 computers

r = number of success = both 2

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=2, p=0.94)$

Now, Probability that both computers are ancient is given by = P(X = 2)

P(X = 2) = $\binom{2}{2}\times 0.94^{2} \times (1-0.94)^{2-2}$

= $1 \times 0.94^{2} \times 1$

= 0.8836

(b) Eight computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = all 8

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=8, p=0.94)$

Now, Probability that all eight computers are ancient is given by = P(X = 8)

P(X = 8) = $\binom{8}{8}\times 0.94^{8} \times (1-0.94)^{8-8}$

= $1 \times 0.94^{8} \times 1$

= 0.6096

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = at least one

p = probability of success which is now the % of computers

that are classified as cutting dash edge, i.e; p = (1 - 0.94) = 0.06

LET X = Number of computers classified as cutting dash edge

So, it means X ~ $Binom(n=8, p=0.06)$

Now, Probability that at least one of eight randomly selected computers is cutting dash edge is given by = P(X $\geq$ 1)

P(X $\geq$ 1) = 1 - P(X = 0)

= $1 - \binom{8}{0}\times 0.06^{0} \times (1-0.06)^{8-0}$

= $1 - [1 \times 1 \times 0.94^{8}]$

= 1 - $0.94^{8}$ = 0.3904

Here, the probability that at least one of eight randomly selected computers is cutting dash edge is 0.3904 or 39.04%.

For any event to be unusual it's probability is very less such that of less than 5%. Since here the probability is 39.04% which is way higher than 5%.

So, it is not unusual that at least one of eight randomly selected computers is cutting dash edge.

7 0

3 years ago

A house is 46.0 ft long and 50 ft wide, and has 8.0-ft-high ceilings. what is the volume of the interior of the house in cubic m

I am Lyosha [343]

Volume of house = 46*50*8=18400 ft^3
Each foot equals 0.3048 m. (exactly).
Therefore 1 ft^3 = 0.3048^3 m^3
Therefore volume of the interior of the house
= 18400 ft^3 * .3048^3 m^3/ft^3
=18400*.3048^3 m^3
=521.0299772928 m^3
=521 m^3 (nearest m^3) ................(a)
or, in cubic centimeters
=521 m^3 * (100cm/m)^3
=521.0299772928 * 100^3 cm^3
=521029977.2928 cm^3
=521029977 cm^3 (nearest cm^3) .........(b)

Answer: see (a) and (b).

4 0

3 years ago

Given that f(x)=6x+2 and g(x)=2x+4/5 solve for g(f(1)) A.1 B.3 C.4 D.8

GrogVix [38]

Answer:

The value of g(f(1)) is 84/5

Step-by-step explanation:

To find the answer to a composite function, start with the function on the inside, which is f(1). So, we input 1 into the f(x) equation and evaluate.

f(x) = 6x + 2

f(1) = 6(1) + 2

f(1) = 6 + 2

f(1) = 8

Now that we have the answer of 8, we can input that in for x in the outside function, which is g(x).

g(x) = 2x + 4/5

g(8) = 2(8) + 4/5

g(8) = 16 + 4/5

g(8) = 84/5

6 0

3 years ago