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NNADVOKAT [17]
3 years ago
9

Which is the image of ABC for a 90° counterclockwise rotation about P?

Mathematics
2 answers:
timofeeve [1]3 years ago
6 0
The answer is EFD because the turn is counterclockwise, around point P

- Your welcome
balu736 [363]3 years ago
5 0

Answer:

The triangle DEF

Step-by-step explanation:

If we see triangle ABC then by observing then we can say BC is base, AC is perpendicular and AB is hypotenuse .

When we rotate triangle ABC counter-clock wise rotation about P then

Then base BC becomes perpendicular of triangle, AC becomes base of triangle and  hypotenuse AB remains same .

We can see this process through diagram.

Hence, the final triangle we obtain after 90° rotation is look similar as triangle DEF

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Which fraction is equivalent to <br><br> 3/5
pentagon [3]

Answer:

12/20

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
You have an equation y=x+7. Is the ordered pair (1,6) a solution? Yes or no?
vaieri [72.5K]
Answer:
no

step-by-step explanation:
y=x+7
x is the slope of 1
7 is the y-intercept
because 7 is the y-intercept and the slope is positive it never touches (1,6)
8 0
3 years ago
What is equivalent to 9 3/4?
Nata [24]

Step-by-step explanation:

We need to say that 9^{3/4} is equivalent to what.

We know that, (3)² = 9

So,

9^{3/4}=((3)^2)^{3/4}\\\\=3^{3/2}

We can write 3^{3/2} =3\times 3^{1/2}

And 3^{1/2}=\sqrt{3}

So,

3\times 3^{1/2}=3\sqrt{3}

So, 9^{3/4} is equivalent to 3\sqrt{3}.

Hence, this is the required solution.

6 0
3 years ago
In January, you deposit $16 in your checking account. Each month, you deposit $15 more than you did the month before. How much m
Leya [2.2K]
You would put 151 dollars in your account at October.
16+15+15+15+15+15+15+15+15+15=151

6 0
3 years ago
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Get the general term for the sequence being your t3 = 11 and the t20 = 244.2
marusya05 [52]

Answer:

nth term = t_{n} = 7.639(1.2)^{n - 1}

Step-by-step explanation:

Let us assume that the given sequence is a G.P.

Now, if the first term of the G.P. is a and the common ratio is r, then

Third term = t_{3} = ar^{2} = 11 .......... (1) and  

20th term = t_{20} = ar^{19} = 244.2 ........... (2)

Now, dividing equation (2) with equation (1) we get

\frac{ar^{19} }{ar^{2} } = \frac{244.2}{11} = 22.2

⇒ r^{17} = 22.2

⇒ r = 1.2.

Hence, from equation (1) we get

a(1.2)² = 11

⇒ a = 7.639 (Approx.)

Therefore, the general term of the sequence i.e. nth term = t_{n} = 7.639(1.2)^{n - 1} (Answer)

5 0
3 years ago
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