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3 years ago

Helpppp Plsssss Asap!! Show your work!! Thank you!!

Mathematics

1 answer:

tia_tia [17]3 years ago

8 0

<h2>Hello!</h2>

The answer is: B) $(x-4)^{2}+1$

Since from the graph we can only see the position of the vertex (4,1), let's find the vertex of the chosen option (B).

$g(x)=(x-4)^{2}+1=x^{2}-8x+16+1=x^{2}-8x+17$

Where:

$a=1\\b=-8\\c=17$

Finding the vertex:

$x=\frac{-b}{2a}=\frac{-(-8)}{2*1}=\frac{8}{2}=4$

So, x-coordinate of the vertex is 4,

Susbtituting x into the function, we can find the y-coordinate

$g(4)=y=4^{2}-8(4)+17=1$

So, y-coordinate of the vertex is 1

Hence,

The Vertex is located at (4,1)

If the vertex is located at (4,1), then the chosen option is correct.

Have a nice day!

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What is nintetty-nine hundredths as a decimal

guapka [62]

It is still 99 Hundredths as a decimal.

8 0

3 years ago

Question 2 of 5

AlekseyPX

Given:

The different recursive formulae.

To find:

The explicit formulae for the given recursive formulae.

Solution:

The recursive formula of an arithmetic sequence is $f(n)=f(n-1)+d, f(1)=a,n\geq 2$ and the explicit formula is $f(n)=a+(n-1)d$ , where a is the first term and d is the common difference.

The recursive formula of a geometric sequence is $f(n)=rf(n-1), f(1)=a,n\geq 2$ and the explicit formula is $f(n)=ar^{n-1}$ , where a is the first term and r is the common ratio.

The first recursive formula is:

$f(1)=5$

$f(n)=f(n-1)+5$ for $n\geq 2$ .

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 5. So, the explicit formula for this recursive formula is:

$f(n)=5+(n-1)(5)$

$f(n)=5+5(n-1)$

Therefore, the correct option is A, i.e., $f(n)=5+5(n-1)$ .

The second recursive formula is:

$f(1)=5$

$f(n)=3f(n-1)$ for $n\geq 2$ .

It is the recursive formula of a geometric sequence with first term 5 and common ratio 3. So, the explicit formula for this recursive formula is:

$f(n)=5(3)^{n-1}$

Therefore, the correct option is F, i.e., $f(n)=5(3)^{n-1}$ .

The third recursive formula is:

$f(1)=5$

$f(n)=f(n-1)+3$ for $n\geq 2$ .

It is the recursive formula of an arithmetic sequence with first term 5 and common difference 3. So, the explicit formula for this recursive formula is:

$f(n)=5+(n-1)(3)$

$f(n)=5+3(n-1)$

Therefore, the correct option is D, i.e., $f(n)=5+3(n-1)$ .

6 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP!! CORRECT ANSWERS ONLY PLEASE!!!

Pepsi [2]

Answer: 8.69 (read explanation)

Step-by-step explanation:

If the one above it is only 8 and x is slightly better it would make much more sense for it to be 8.69..... try it, it sounds quit accurate.

6 0

3 years ago

A brick is thrown upward from the top of a building at an angle of 250 above the horizontal, and with an initial speed of 15 m/s

mojhsa [17]

Answer:

(a) 25.08 m

(b) 2.05 m

Step-by-step explanation:

Let the height of the building be 'h'.

Given:

Angle of projection is, $\theta=25$ °

Initial speed is, $u=15\ m/s$

Time of flight is, $t=3.0\ s$

(a)

Consider the vertical motion of the brick.

Vertical component of initial velocity is given as:

$u_y=u\sin\theta\\\\u_y=15\sin(25)=6.34\ m/s$

Vertical displacement of the brick is equal to the height of the building.

So, vertical displacement = $-h$ (Negative sign implies downward motion)

Acceleration is due to gravity in the downward direction. So,

Acceleration is, $g=-9.8\ m/s^2$

Now, using the following equation of motion;

$-h=u_yt+\frac{1}{2}gt^2\\-h=6.34(3)-\frac{9.8}{2}(3)^2\\\\-h=19.02-44.1\\\\-h=-25.08\\\\h=25.08\ m$

Therefore, the building is 25.08 m tall.

(b)

Let the maximum height be 'H'.

At maximum height, the vertical component of velocity is 0 as the brick stops temporarily in the vertical direction.

So, $v_y=0\ m/s$

Now, using the following equation of motion, we have:

$v_y^2=u_y^2+2gH\\\\0=(6.34)^2-2\times 9.8\times H\\\\19.6H=40.2\\\\H=\frac{40.2}{19.6}=2.05\ m$

Therefore, the maximum height of the brick is 2.05 m.

5 0

3 years ago

Which statement about convergent infinite

balandron [24]

Answer:

B) Convergent infinite geometric series sum to a single value

Step-by-step explanation:

An infinite geometric series of the form $\[ \sum_{r=1}^{\infty} ar^{n-1}$ converges if $|r|$ , so the summation of the series will result in a single value if that is true.

8 0

3 years ago

Helpppp Plsssss Asap!! Show your work!! Thank you!! ​

Helpppp Plsssss Asap!! Show your work!! Thank you!!