Answer:
I think 29
I don't know if it's right
Remember, these are quadrilaterals, so they must add up to 360°. Just add up the angles and then do 360 minus that number to solve for x.
Therefore:
1. 118 + 90 + 99 = 307
360 - 307 = 53
2. 110 + 96 + 78 = 284
360 - 284 = 76
3. 48 + 118 + 97 = 263
360 - 263 = 97
4. 105 + 99 + 64 = 268
360 - 268 = 92
5. 103 + 63 + 113 = 279
360 - 279 = 81
6. 95 + 80 + 88 = 263
360 - 263 = 97
Answer:
B. two
explanation:
i took the test
hope this helps. have a great day!!
Step-by-step explanation:
Draw diagonal AC
The triangle ABC has sides 17 and 25
Say AB is 17, BC is 25
Draw altitude on side BC from A , say h
h = 17 sin B
Area = 25*17 sin B = 408
sin B = 24/25
In ∆ ABC
Cos B = +- 7/25
= 625 + 289 — b^2 / 2*25*17
b^2 = 914 — 14*17 = 676
b = 26
h = 17*24/25 = 408/25 = 16.32
Draw the second diagonal BD
In ∆ BCD, draw altitude from D, say DE =h
BD^2 = h^2 + {(25 + sqrt (289 -h^2) }^2
BD^2 = 16.32^2 + (25 + 4.76)^2
= 885.6576 + 266.3424
BD = √ 1152 = 33.94 m
If you look from the points at angle 73, to 42, to 131, to z, the shape makes a quadrilateral.
Since the total of the interior angles in a quadrilateral add up to 360 you make an equation:
360 = 131 + 73 + 42 + 7 + x
Re-arrange the equation to get the x alone, by subtracting:
360 - 131 - 73 - 42 = x
114 = x
So x = 114 degrees<span />
