Answer:
shows correct substitution of the values a, b, and c from the given quadratic equation into quadratic formula.
Step-by-step explanation:
Given: The quadratic equation
We have to show the correct substitution of the values a, b, and c from the given quadratic equation into quadratic formula.
The standard form of quadratic equation is then the solution of quadratic equation using quadratic formula is given as
Consider the given quadratic equation
Comparing with general quadratic equation, we have
a = -3 , b = -2 , c = 6
Substitute in quadratic formula, we get,
Simplify, we have,
Thus, and x_{2}=\frac{2-\sqrt{76} }{-6}
Simplify, we get,
Thus, shows correct substitution of the values a, b, and c from the given quadratic equation into quadratic formula.
Answer:
Step-by-step explanation:
3x – y + 2z = 6 - - - - - - - - - 1
-x + y = 2 - - - - - - - - - - - - -2
x – 2z = -5 - - - - - - - - - - - -3
From equation 2, x = y - 2
From equation 3, x = 2z - 5
Substituting x = y - 2 and x = 2z - 5 into equation 1, it becomes
3(y - 2) – y + 2z = 6
3y - 6 - y + 2z = 6
3y - y + 2z = 6 + 6
2y + 2z = 12 - - - - - - - - - 4
3(2z - 5) – y + 2z = 6
6z - 15 - y + 2z = 6
- y + 6z + 2z = 6 + 15
- y + 8z = 21 - - - - - - - - - - 5
Multiplying equation 4 by 1 and equation 5 by 2, it becomes
2y + 2z = 12
- 2y + 16z = 42
Adding both equations
18z = 54
z = 54/18 = 3
Substituting z = 3 into equation 5, it becomes
- y + 8×3 = 21
- y + 24 = 21
- y = 21 - 24 = - 3
y = 3
Substituting y = 3 into equation 2, it becomes
-x + 3 = 2
- x = 2 - 3 = -1
x = 1
The circumference of a circle is all around the circle
The diameter is a line that crosses straight across a circle
And the radius is half the diameter :)
Answer:
2250 words in 30 minutes.
Step-by-step explanation:
:)
Every triangle is equal to 180 degrees so u need to subtract what is already shown form 180,, 180-120=60 and then 60-40 20 so the final degree is 20 ,,,,, to check u can add them all together if if they equal 180 u should be g
