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3 years ago

Find the mean absolute deviation of the set of data 3,8,10,12,15

2 answers:

4 0

3 + 8 + 10 + 12 + 15 = 48

48 / 5 = 9.6 or 10

3 - 7
8 - 2
10 - 0
12 - 2
15 - 5

7 + 2 + 0 + 2 + 5 = 16

16 / 5 = 3.2 or 3

The Mean Absolute Deviation is approximately 3

Post brainliest if this helped :D

Andre45 [30]3 years ago

4 0

The mean absolute deviation of this data set is 3.28 or 3. Good luck!

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marusya05 [52]

So it is really easy to solve firstly we can see how much does the first 10 boxes make which makes around 55$ obviously. Secondly 45$ for the next 10 boxes.

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3 years ago

The first step when dividing 9m2 − 4m − 6 by 3m is shown. Which could be the next step? 3m − − 3m − − 3m − − 3m − −

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2 years ago

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ss7ja [257]

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2 years ago

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Which calculation would result in the decimal point moving two spaces to the right in a decimal number?

Burka [1]

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3 years ago

A red kangaroo hops at an average speed of 20km per hour. How fast is this in meters per minute?

masya89 [10]

Answer:

333.3 meters per minute

Step-by-step explanation:

The best way to solve this problem is using dimensional anaysis. First, we write out our starting units, that being 20km/1hr. We have to keep in mind that we want to change the kilometers to meters and the hours to minutes.

$\frac{20km}{1hr}$

We know that there are 1000 meters in 1 kilometer. We add this to the dimensional analysis as 1000m/1km. We write it as this because we want the kilometers to cancel each other out. We only want the meters.

$= \frac{20km}{1hr} *\frac{1000m}{1km} ...$

We also know that 1 hour is 60 minutes. We add this to the analysis as well so that the hours cancel each other.

$= \frac{20km}{1hr} *\frac{1000m}{1km} * \frac{1hr}{60min}$

We now solve this expression. Since both the kilometers and the hours cancel out, we have meters per minute as our unit. All that's left are the numbers.

= (20*1000*1)/(1*1*60) m/min

= 333.3 meters per minute

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3 years ago