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Serhud [2]
3 years ago
15

Which binomial is a factor of 49x2 + 84 xy + 36y2?

Mathematics
1 answer:
skad [1K]3 years ago
5 0

Answer:

(7x+6y) is a binomial factor of the given expression  49x^2+84xy+36y^2

Therefore  49x^2+84xy+36y^2=(7x+6y)(7x+6y)

Step-by-step explanation:

Given expression is 49x^2+84xy+36y^2

To find the binomial factor :

49x^2+84xy+36y^2

Rewritting the above expression as

=7^2x^2+2(7)(6)xy+6^2y^2

=(7x)^2+2(7x)(6y)+(6y)^2

=(7x+6y)^2 ( using the formula =(a+b)^2=a^2+2ab+b^2 here a=7x and y=6y )

=(7x+6y)(7x+6y) ( using the formula =(a+b)^2=(a+b)(a+b) )

Therefore  49x^2+84xy+36y^2=(7x+6y)(7x+6y)

(7x+6y) is a binomial factor of the given expression  49x^2+84xy+36y^2

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Answer:

y=3

Step-by-step explanation:

Since g(x)=0, you input 0 into every x

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Which then becomes:

y=0+3

Take out the 0 and there's your answer

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2 years ago
What is domain restrictions and what causes them?
MakcuM [25]
Domain restrictions are values of x which are not acceptable in a function.

They may be arbitrary because we simply want to ignore them. eg y = x^2 between 0 and 4

They may make no sense in the context, eg graph a compounding investment over next 20 years.
Negative values for x make sense here.

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8 0
3 years ago
The sum of the digits in a two digit number is 14. If you reverse and double the original number, and then add the result to the
gtnhenbr [62]

Answer:

Step-by-step explanation:

Let the two digits be x and y, where x is the tens digit and y is the units (ones) digit.

Then the number is 10x + y.

From the question,

The sum of the digits in a two digit number is 14,

That is, x + y = 14 ....... (1)

Also, from the question,

If you reverse and double the original number, and then add the result to the original number, the sum is 222

If the number is reversed, the new number will be 10y + x; and if this is doubled, we will get 2(10y + x).

Now, if this is added to the original number (10x + y), the sum is 222.

That is,

2(10y + x) + (10x + y) = 222

Then,

20y + 2x + 10x + y = 222

12x + 21y = 222 ........ (2)

Now, we will bring the two equations together and solve simultaneously.

x + y = 14 ....... (1)

12x + 21y = 222 ........ (2)

From equation (1)

x + y = 14

Then, x = 14 - y ...... (3)

Substitute the value of x in equation (3) into equation (2)

12x + 21y = 222

12(14 - y) + 21y = 222

168 - 12y + 21y = 222

168 + 9y = 222

9y = 222 - 168

9y = 54

∴ y = 54/9

y = 6

To determine x, substitute the value of y into equation (3)

x = 14 - y

∴ x = 14 - 6

x = 8

∴ x = 8 and y = 6

Recall that, the two digits are x and y, where x is the tens digit and y is the units (ones) digit.

Hence, the original number is 86.

8 0
3 years ago
Which relation is also a function?
Lelu [443]

Answer:

D because if you graphed the others they wouldn't pass the vertical line test

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