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Flauer [41]
3 years ago
12

. In a physics lab, you attach a 0.200-kg air-track glider to the end of an ideal spring of negligible mass and start it oscilla

ting. The elapsed time from when the glider first moves through the equilibrium point to the second time it moves through that point is 2.60 s. Find the spring’s force constant
Physics
1 answer:
cluponka [151]3 years ago
6 0

Answer:

Spring constant, k = 1.16 N/m

Explanation:

It is given that,

Mass of the air track, m = 0.2 kg

Time, t = 2.6 s

Let T is the time period of the spring. The expression for the time and spring constant is given by :

T=2\pi \sqrt{\dfrac{m}{k}}

k=\dfrac{4\pi^2m}{T^2}

k=\dfrac{4\pi^2\times 0.2}{(2.6)^2}

k = 1.16 N/m

So, the spring’s force constant is 1.16 N/m. Hence, this is the required solution.

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what are you trying to ask?

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A cylindrical log 18 cm in diameter and 75 cm long is glowing red hot in a fireplace. if it's emitting radiation at the rate of
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Here we are approximating the log to be a black body. 

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