To solve the problem it is necessary to take into account the concepts of the kinetic equations for the description of the torque at the rate of force and distance.
By definition the torque is given by,
where,
For the problem in question the mass of the trophy is 1.64Kg and the distance of the tropeo to the board (the shoulder) is 0.655m
PART A) For part A, the torque with the given mass and the stipulated torque in the horizontal plane must be calculated as well,
For Newton's second law
PART B) For part B there is an angle of 26 degrees with respect to the horizontal, therefore to know the net torque it is necessary to know the horizontal component to the formed angle, that is,
Answer:
2.47 m
Explanation:
Let's calculate first the time it takes for the ball to cover the horizontal distance that separates the starting point from the crossbar of d = 52 m.
The horizontal velocity of the ball is constant:
and the time taken to cover the horizontal distance d is
So this is the time the ball takes to reach the horizontal position of the crossbar.
The vertical position of the ball at time t is given by
where
is the initial vertical velocity
g = 9.8 m/s^2 is the acceleration of gravity
And substituting t = 2.56 s, we find the vertical position of the ball when it is above the crossbar:
The height of the crossbar is h = 3.05 m, so the ball passes
above the crossbar.
Answer:electrostatic interactions, hydrogen bonding, van der waals interactions.
Explanation:the above listed are the interaction that that contribute
I think most likely the answer is the first one. meeting other students. if not then maybe the second one, highly motivated.
Given that the arc length is:
s = ∫ √[1² + (dy/dx)²] dx
<span>So arc length between the two points is then: </span>
<span>s = 2*20sinh(x/20)
= 40sinh(x/20) </span>
<span>The straight distance between the two points is : d = 2x </span>
<span>So, x = d/2.
= 40/2
= 20 m </span>
<span>Plug this into the arc length equation to get:
s = 40sinh[20/20)]
=40* ½ (e - 1/e) </span>
<span> = 47 m</span>