The "ringing sound" are actually the soundwaves travelling from the phone to your ears.
50 g = 0.5 kg. a = 5 / 0.5 = 10 m/s^2.
Explanation:
We have,
Mass of an object is 0.5 kg
Force constant of the spring is 157 N/m
The object is released from rest when the spring is compressed 0.19 m.
(A) The force acting on the object is given by :
F = kx
(B) The force is simply given by :
F = ma
a is acceleration at that instant
Answer:
a = (v₃₂ - v₂₁) / (t₃₂ -t₂₁)
Explanation:
This is an exercise of average speed, which is defined with the variation of the distance in the unit of time
v = (y₃ - y₂) / (t₃-t₂)
the midpoint of a magnitude is the sum of the magnitude between 2
t_mid = (t₂ + t₃) / 2
the same reasoning is used for the mean acceleration
a = (v_f - v₀) / (t_f - t₀)
in our case
a = (v₃₂ - v₂₁) / (t₃₂ -t₂₁)
The problem is a free fall problem as the camera drops. The vertical velocity is zero. It is the action of gravity that takes place here. To calculate the time it takes to reach the ground, we do as follows:
t = √2y/g = √(2)(70)/9.81 = 3.78 s
The velocity as it impacts the ground would be,
v = √2gy = 37.04 m/s
Hope this helps.