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Shkiper50 [21]
3 years ago
15

Hola ( Hey ) who wanna be friends?

Physics
2 answers:
il63 [147K]3 years ago
8 0

Answer:

I do

Explanation:

I want to be friend

Naddik [55]3 years ago
8 0
Hola, Maybe i wanna be ur frienddd
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A school bus full of students drives down the road. Because it is moving, it has 1.potential energy because it has the ability t
weqwewe [10]
<span>Kinetic energy because it is taking the students to school.</span>
3 0
3 years ago
Read 2 more answers
A playground carousel is free to rotate about its center on frictionless bearings, and air resistance is negligible. The carouse
Sidana [21]

Answer:

m = 35.98 Kg ≈ 36 Kg

Explanation:

I₀ = 125 kg·m²

R₁ = 1.50 m

ωi = 0.600 rad/s

R₂ = 0.905 m

ωf = 0.800 rad/s

m = ?

We can apply The law of conservation of angular momentum as follows:

Linitial = Lfinal

⇒    Ii*ωi = If*ωf   <em>(I)</em>

where    

Ii = I₀ + m*R₁² = 125 + m*(1.50)² = 125 + 2.25*m

If = I₀ + m*R₂² = 125 + m*(0.905)² = 125 + 0.819025*m

Now, we using the equation <em>(I) </em>we have

(125 + 2.25*m)*0.600 = (125 + 0.819025*m)*0.800

⇒  m = 35.98 Kg ≈ 36 Kg

5 0
3 years ago
What will be the effect on each of these objects, the bowling ball and the baseball?
Nastasia [14]
What effect man there are a million effects the only one that arent true are fusion or fission and magnetism unless that bowling ball is iron 
7 0
3 years ago
To practice problem-solving strategy 22.1: gauss's law. an infinite cylindrical rod has a uniform volume charge density ρ (where
BabaBlast [244]

Let say the point is inside the cylinder

then as per Gauss' law we have

\int E.dA = \frac{q}{\epcilon_0}

here q = charge inside the gaussian surface.

Now if our point is inside the cylinder then we can say that gaussian surface has charge less than total charge.

we will calculate the charge first which is given as

q = \int \rho dV

q = \rho * \pi r^2 *L

now using the equation of Gauss law we will have

\int E.dA = \frac{\rho * \pi r^2* L}{\epcilon_0}

E. 2\pi r L = \frac{\rho * \pi r^2* L}{\epcilon_0}

now we will have

E = \frac{\rho r}{2 \epcilon_0}

Now if we have a situation that the point lies outside the cylinder

we will calculate the charge first which is given as it is now the total charge of the cylinder

q = \int \rho dV

q = \rho * \pi r_0^2 *L

now using the equation of Gauss law we will have

\int E.dA = \frac{\rho * \pi r_0^2* L}{\epcilon_0}

E. 2\pi r L = \frac{\rho * \pi r_0^2* L}{\epcilon_0}

now we will have

E = \frac{\rho r_0^2}{2 \epcilon_0 r}


7 0
4 years ago
Gardeners understand that plants have specific pH requirements. Most plants thrive in soil with a pH that is slightly acidic, ne
Delvig [45]

Answer:

D) Add a base like limestone or calcium carbonate.

Explanation:

-To reduce the soil's pH, you need to add an alkaline or base solution.

-Calcium carbonate has an alkanizing property and forms a carbonic acid and calcium hydroxide when dissolved in water.

-The solution will reduces the soil's pH.

8 0
3 years ago
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